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2 years ago

Scott makes $12 per hour babysitting and $8 per hour working at the grocery store. He will need to make

Mathematics

1 answer:

cricket20 [7]2 years ago

3 0

What am I solving for it doesn’t give a specific question.

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What is the slope simplify your answer and write it as a proper fraction, improper fraction, or integer

worty [1.4K]

Take 2 points: (0, 70) (30, 80)

SLOPE FORMULA: y2 -y1 / x2 - x1

y2 - y1: 80 - 70 = 10

x2 - x1: 30-0 = 30

10 / 30

simplify: 1/3

This is a PROPER FRACTION

5 0

3 years ago

A rectangle has a length this is three times its width. If the area of the rectangle is 27 square feet, what are the dimensions

yuradex [85]

Answer:

The width of the rectangle is 3 and the width is 9. Those are reasonable measurements.

Step-by-step explanation:

6 0

3 years ago

Find the slope of the line that passes through

Crazy boy [7]

Slope: (y2-y1)/(x2-x1)
(-3+5)/(-1-7) = 2/-8 = -1/4
The answer is d) -1/4

3 0

3 years ago

The bill for a group of eight people at a restaurant came to $196. Because they are a large party, the restaurant also adds an 1

Iteru [2.4K]

I did the multiplications and I think it is 1,568

8 0

2 years ago

(-3)³ + (-4)² - (-2)³

AleksAgata [21]

Answer:

$=-3$

Step-by-step explanation:

$\left(-3\right)^3+\left(-4\right)^2-\left(-2\right)^3\\Follow\:the\:PEMDAS\:order\:of\:operations\\\mathrm{Calculate\:exponents}\:\left(-3\right)^3\::\quad -27\\\left(-3\right)^3\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\mathrm{if\:}n\mathrm{\:is\:odd}\\\left(-3\right)^3=-3^3=-27\\=-27+\left(-4\right)^2-\left(-2\right)^3\\\mathrm{Calculate\:exponents}\:\left(-4\right)^2\::\quad 16\\\left(-4\right)^2$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}\\\left(-4\right)^2=4^2=16\\=-27+16-\left(-2\right)^3\\\mathrm{Calculate\:exponents}\:\left(-2\right)^3\::\quad -8\\\left(-2\right)^3\\\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=-a^n,\:\mathrm{if\:}n\mathrm{\:is\:odd}\\\left(-2\right)^3=-2^3=-8\\=-27+16-\left(-8\right)\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:-27+16-\left(-8\right)\::\quad -3\\-27+16-\left(-8\right)$

$-27+16=-11\\=-11-\left(-8\right)\\\mathrm{Apply\:rule\:}-\left(-a\right)\:=\:+a\\-\left(-8\right)=+8\\=-11+8\\-11+8=-3\\=-3$

8 0

2 years ago

Read 2 more answers