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Ksivusya [100]
3 years ago
7

A mixed number is greater than 3.62

Mathematics
1 answer:
Valentin [98]3 years ago
5 0
The mixed number would be larger depending on what it is...


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Which statement is true about the measures of center of the practice times?
steposvetlana [31]

Correct answer is C..................

5 0
3 years ago
The area of two similar triangles are 50dm^2 and 32dm^2. The sum of their perimeters is 117dm. What us the perimeters of each of
Kay [80]

Answer:

Perimeter of one triangle is 65 dm

Perimeter of other triangle is 52 dm

Step-by-step explanation:

Please remember the concept

If sides are in the ratio of a:b

Then the area in the ratio of a^{2} :b^{2}

It is given sum of their perimeter is 117.

Let the small triangle has perimeter as x.

So, perimeter of big triangle is 117-x.

So, we can set up equation as

\frac{50}{32} =\frac{x^{2} }{(117-x)^{2} }

Cross multiply

50(117-x)^2 =32x^2

Expand the left side

50(13689 -234x+x^{2} )=32x^{2}

Distribute the left side

684450-11700x+50x^{2}=32x^{2}

Subtract both sides 32x^{2} and rewrite it 18x^{2} -11700x+684450=0

Solve this quadratic for x.

Divide both sides of the equation by 18 to simplify.

x^{2}-650 x+38025=0

Now, if possible let's factor

Find two integers whose multiplication is 38025 but adds to -650.

-65 and -585 works.

So, we can rewrite it as

(x -65)(x-585) =0

Solve them using zero product property

x=65, x=585

So, x=65 works here.

So, perimeter of one triangle is 65 dm

Perimeter of other triangle is 117-65= 52 dm

5 0
3 years ago
How do I calculate 1/5 of 125
Brrunno [24]

Answer:

You do 1/5 x 125 which equals 25

Step-by-step explanation:

4 0
3 years ago
A runner jogged 4 miles in ten laps around a circular
dybincka [34]

Answer:

.1273 mi = 627.2 feet

c = 2\pir

.4 = 2\pir

r = \frac{.4}{2\pi }

r = \frac{.2}{\pi }

d = \frac{.4}{\pi }

d = .1273 mi = 627.2 feet

Step-by-step explanation:

4 0
3 years ago
SOLVE USING ELIMINATION *20 POINTS*
V125BC [204]

1. No answer ( may be due to incorrect question)

2. x = -3

y = 4

3. x= 4

y = 2

4.x = -63/40

y= -19/20

Step 1

Multiply equation 1 by the coefficient of x in equation 2

Multiply equation 2 by the coefficient of x I'm equation 1

(after completing this step you will derive equation 3 and 4 )

Step 2

Subtract equation 4 from equation 3

Step 3

Divide both sides of the equation by the coefficient of y

Step 4

substitute your value for y in equation 1 or 2

(after this you will derive the values of x)

Note : This method is for the Elimination of x

I hope it helps

5 0
3 years ago
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