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1 year ago

Decide whether the triangles are similar. If so, determine the appropriate expression to solve for x.

Mathematics

1 answer:

ser-zykov [4K]1 year ago

3 0

Answer:

The last answer is correct.

Step-by-step explanation:

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You should solve the answer for z not m pls

mariarad [96]

Step-by-step explanation:

we can factor out z

so that'll be

z((1/m)-(1/n))=1

divide by the value in parentheses on both sides

z=1/((1/m)-(1/n))

I can't tell if there's more the problem wants you to do. I could rewrite the equation on paper more easily, but I don't have one on hand

5 0

2 years ago

Read 2 more answers

Help! Exponential Equation WITHOUT CALCULATOR

ale4655 [162]

$
1.
(2^{x} -2^{-x})^{2} = 4^{2} \\ \\2^{2x}-2*2^{x}*2^{-x} + 2^{-2x} =4^{2} \\ \\2^{2x}-2*2^{x-x} + 2^{-2x} =4^{2} \\ \\ 2^{2x}+ 2^{-2x} - 2=16 \\ \\ 2^{2x}+ 2^{-2x} = 18

\\ \\ 2.( 2^{x})^{3} - (2^{-x}^) ^{3}= (2^{x} -2^{-x})(2^{2x}+2^{x}*2^{-x}+2^{-2x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+2^{x}*2^{-x})
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})(2^{2x}+2^{-2x}+1)
\\ \\ ( 2^{x})^{3} - (2^{-x}^)^{3}=(2^{x} -2^{-x})((2^{2x}+2^{-2x})+1)
$

$\\ \\ ( 2^{x})^{3} - (2^{-x})^{3} =(4)((18)+1)= 76
\\ \\ 2^{3x}-2^{-3x} =76
$

4 0

3 years ago

Hi!

suter [353]

Answer:

1 median=60.3

2 missing number=38

Step-by-step explanation:

1 45+55+76+y+88+54/6

316+y/6=63.6

316+x381.6

x=381.6-316=65.6

2M4 =63

60-62+92+x/4=63

214+x=252

x=252-214

=38

7 0

3 years ago

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2x+20=-3x-25 help me solve it

zysi [14]

The correct answer is x= -9. Hope this helps!!

8 0

3 years ago

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Select all the pairs that could be reasonable approximations for the diameter and circumference of a circle. Explain your reason

rosijanka [135]

Answer:it’s 19 inches and 60 inches.

Step-by-step explanation:

3 0

3 years ago