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ziro4ka [17]
2 years ago
7

A line with slope

Mathematics
1 answer:
spayn [35]2 years ago
6 0

Answer:

(0, 8/3) = y-intercept

Step-by-step explanation:

I chose to find the y-intercept since it is easy to find with the given information.

The equation for a line is y = mx + b

To find the y-intercept, we must plug in the info we have and solve for b:

4 = -1/3 (-4) + b

4 = -4/3 + b

8/3 = b

To find a point on the line, you also could have added -1 to 4 and 3 to -4 since slope means rise/run or change in y/change in x:

(y - 1) / (x + 3) = (4 - 1) / (-4 + 3) = (3, -1) (flip since it's the y and x coordinate) = (-1, 3)

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3 years ago
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My cell phone charges me $100 to register and then $0.10 per minute. How much will I be charged for 55 minutes? explain why this
Arlecino [84]

Answer:

You will be charged $5.5 in 55 minutes.

Step-by-step explanation:

Just multiply 0.10 by 55 and you get $5.5 dollars.

And no I don't think this is a  Linear equation. Its not a linear equation because you have to set up a ratio to figure this out. Not a whole equation. So, Its more like a ratio

8 0
3 years ago
If Valerie deposited 12,000 into an account threat earns 15% simple annual interest how much money will she have after 3 years
Ad libitum [116K]

Answer:

The amount which she will have into account after 3 years is  17,400  unit

Step-by-step explanation:

Given as :

The principal which is deposited into an account = 12,000  unit

The rate of interest simple annual = 15%

The Time period = 3 years

Let The amount which she have after 3 years = A  unit

<u>From simple Interest method</u>

Simple Interest = \frac{Principal\times Rate\times Time}{100}

Or , Simple Interest = \frac{12,000\times 15\times 3}{100}

Or,  Simple Interest = \frac{540,000}{100}

∴    Simple Interest = 5,400  unit

Now,

Amount = Principal + Simple Interest

Or, A =  12,000  unit + 5,400  unit

∴   A =  17,400  unit

Hence The amount which she will have into account after 3 years is  17,400  unit . Answer

6 0
3 years ago
Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa
Furkat [3]

Given:

Distance between two buildings = 3x^3- x^2 + 7x +100 feet apart.

Distance between highway and one building = 2x^2 + 7x feet.

Distance between highway and second building = x^3 + 2x^2 - 18 feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)

W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18

Combining like terms, we get

W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)

W=2x^3-5x^2+0+118

W=2x^3-5x^2+118

Therefore, the width point highway is 2x^3-5x^2+118.

3 0
3 years ago
A business tenant has a percentage lease stating rent payment is greater of 2% of the business's total gross sales volume or a m
kaheart [24]

Answer:

The answer is $12,000. 12 months × $1,000 per month = $12,000 minimum annual base rent; $435,000 gross sales × 2% = $8,700. The tenant paid $12,000 because the minimum base rent was more than the percentage of gross sales.

Step-by-step explanation:

5 0
3 years ago
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