Question

The area of the indoor sports exhibition is shown below. What is its perimeter? m What is its area? m2

Answer 1

Answer:

Area = 3097.96$m^{2}$

Perimeter = 270.96m

Step-by-step explanation:

Step 1: State the shapes making up the indoor sports exhibiti$\pi$on

2 rectangles

1 semi circle

Step 2: Find the area and perimeter of the shapes

ARectangle1 = lw = (10)(40) = 400m^2

PRectangel1 = 2l + w = 2(10) + 40 = 60m

ARectangle2 = lw = (33)(68) = 2244m^2

PRectangel2 = l + w = 33 + 68 = 101m

ASemiCicle = $\frac{\pi r^{2}}{2} =\frac{\pi 17^{2} }{2} =\frac{289\pi }{2}=144.5\pi=453.96m^{2}$

PSemiCircle = $2\pi r=2\pi(17)=35\pi =109.96m$

Step 3: Add up the areas and perimeters

Area = 400 + 2244 + 453.96

Area = 3097.96$m^{2}$

Perimeter = 60 + 101 + 109.96

Perimeter = 270.96m

Therefore the area of the indoor sports exhibition is 3097.96$m^{2}$ and the perimeter is 270.96 m