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2 years ago

Consider the first four terms of the sequence below. -3, -12, -48, -192, . . . what is the 8th term of this sequence?

Mathematics

1 answer:

Serga [27]2 years ago

3 0

Answer: -49152

Step-by-step explanation: the pattern here is that each term is subtracting 3 times its absolute value. Going from -3 to -12 there is a difference of 9 which is 3 times to absolute value of -3. So, the sequence will continue like this : -192, - 768, -3072, - 12288, -49152.

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3 years ago

50 point HELP ASAP Question: A rectangle has sides measuring (3x + 8) units and (6x + 5) units.

cluponka [151]

Answer:

see below

Step-by-step explanation:

(3x + 8) units by (6x + 5) units.

A = l*w

= (3x+8)(6x+5)

Distribute

3x*(6x+5) + 8(6x+5)

18x^2 +15x + 48x +40

Combine terms

18x^2+63x+40 units^2

The degree is 2 ( the highest power of x)

This is a trinomial ( it has 3 terms)

Multiplication is closed for polynomial multiplication

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3 years ago

Im bad at math and i need help

Colt1911 [192]

I think it would just be n rad n

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2 years ago

Read 2 more answers

cupoosta [38]

Answer:

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3 years ago

Read 2 more answers

What is the slope-intercept form for (1,6) and (2,5)

patriot [66]

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-6}{2-1}\implies \cfrac{-1}{1}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-6=-1(x-1) \\\\\\ y-6=-x+1\implies y=-x+7$

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3 years ago