How many solutions exist for the given equation?
1 answer:
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Answer:
Circle 1=6x+2y
Rectangle 4 = 3x+y
Circle 4 = 5x
Step-by-step explanation:
4x+3y and 2x-y can be added to find result for the circle.
Let C1 represent circle 1
4x+3y+2x-y=C1\\
Combining\:like\:terms\\
4x+2x+3y-y=C1
6x+2y=C1
So, The result is: C1=6x+2y
Now, We need to solve:
Let R1 represent rectangle 4
x+4y + R1 = 4x+5y
R1=4x+5y-(x+4y)
R1=4x+5y-x-4y
R1=4x-x+5y-4y
R1=3x+y
So, Solving x+4y + R1 = 4x+5y, We get R1 = 3x+y
Now, We need to solve the equation:
Let C4= Circle 4
2x-y+3x+y=C4
Combining the like terms
2x+3x-y+y=C4
5x=C4
So, Solving 2x-y+3x+y=C4 we get C4 = 5x
Answer:
The answer is "".
Step-by-step explanation:
Therefore in this question the "bh" were the multiplied and these values includes the variable which is solving by the isolating of "b".
Let's Divides the both sides for h.