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2 years ago

How many solutions exist for the given equation?

Mathematics

1 answer:

irakobra [83]2 years ago

7 0

Answer:

Its infinite solutions

Step-by-step explanation:

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What is an equation of the line that passes through the points (-1, 6) (−1,6) and (-1, -5) (−1,−5)

slavikrds [6]

Answer:

x = -1

Step-by-step explanation:

You can write the equation of the line by finding the slope between the points and substitute it with a point into the point slope form.

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{6--5}{-1--1} =\frac{11}{0} = und$

These points have a slope which is undefined. This means it is a vertical line that crosses through the x-axis at the x-coordinate of both points -1. The equation is x = -1.

8 0

3 years ago

4/3 to the third power as a simplified fraction

zloy xaker [14]

Answer:

64/27

Step-by-step explanation:

(4/3)^3=(4/3)*(4/3)*(4/3)=64/27

6 0

3 years ago

Read 2 more answers

Find the area of the shaded porrion

stich3 [128]

Answer: 111.72 m^2 if they want round its 112

Is from O to C 14m

A=pixr^2

3.14x14^2= 615.44 m/2 half circle = 307.72

Area of triangle A= 1/2bh. .5x28x14=196

307.72-98=196= 111.72 m^2

Step-by-step explanation:

3 0

3 years ago

The coordinates of the endpoints of ST are (-2,3) and (3, y) respectively supposethe distance between s and t us 13 units.What v

igor_vitrenko [27]

Answer:

The values of y would be -9 and 15

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$d=13\ units$

S(-2,3) and T(3,y)

substitute the given values in the formula and solve for y

$13=\sqrt{(y-3)^{2}+(3+2)^{2}}$

$13=\sqrt{(y-3)^{2}+25}$

squared both sides

$169=(y-3)^{2}+25$

$(y-3)^{2}=169-25$

$(y-3)^{2}=144$

take square root both sides

$y-3=(+/-)12$

$y=3(+/-)12$

$y=3(+)12=15$

$y=3(-)12=-9$

therefore

The values of y would be -9 and 15

5 0

3 years ago

The circumference of Circle K is $\pi$ . The circumference of Circle L is $4\pi$ . Two circles, one labeled "Circle K" and the o

timurjin [86]

Answer:

Step-by-step explanation:

Given the circumference of Circle K = π

circumference of Circle L = 4π

Ratio of their circumferences = Ck/Cl

Ratio of their circumferences = π/4π

Ratio of their circumferences = 1/4 = 1:4

For their radii

C = 2πr

for circle k with circumference π

π = 2πrk

1 = 2rk

rk = 1/2

for circle l with circumference 4π

4π = 2πr

4 = 2r

r = 4/2

rl = 2

ratio

rk/rl = 1/2/2

rk/rl = 1/4 = 1:4

for the areas

Area of a circle = πr²

for circle k

Ak = π(1/2)²

Ak = π(1/4)

Ak = π/4

for circle l

Al = π(2)²

Al = 4π

Ratio of their areas

Ak/Al = π/4/(4π)

Ak/Al = π/16π

Ak/Al = 1/16 = 1:16

3 0

3 years ago