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Romashka [77]
3 years ago
9

How many solutions exist for the given equation?

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

Its infinite solutions

Step-by-step explanation:

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b) How many ways can you deal cards (from a deck of 52) to 4 people when each player gets 7 cards. 2 hidden and 5 visible. Assum
Mariana [72]

Answer:

{52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

Step-by-step explanation:

The dealing of the cards can be seen in the following way:

We first have to choose which 7 cards are going to be dealt to the 1st player. So we have to pick 7 cards out of the 52 available cards. This can be done in {52 \choose 7} ways. Now that we have chosen which 7 cards are going to be dealt to the 1st player, we have to choose which 2 of them are going to be the hidden ones. So we have to pick 2 cards out of the 7 cards to be the hidden ones. This can be done in {7 \choose 2} ways. At this point we now know which cards are being dealt to the 1st player, and which ones are hidden for him. Then we have to choose which 7 cards to deal to the 2nd player, out of the remaining ones. So we have to pick 7 out of 52-7=45. (since 7 have been already dealt to the 1st player). This can be done in {45 \choose 7}. Then again, we have to pick which 2 are going to be the hidden cards for this 2nd player. So we have to pick 2 out of the 7. This can be done in {7 \choose 2} ways. Then we continue with the 3rd player. We have to choose 7 cards out of the remaining ones, which at this point are 52-7-7=38. This can be done in {38 \choose 7}. And again, we have to choose which ones are the hidden ones, which can be chosen in {7 \choose 2} ways. Finally, for the last player, we choose 7 out of the remaining cards, which are 52-7-7-7=31. This can be done in {31 \choose 7} ways. And choosing which ones are the hidden ones for this player can be done in {7 \choose 2} ways. At the end, we should multiply all our available choices on each step, to get the total choices or total ways to deal the cards to our 4 players (since dealing the cards is a process of several steps with many choices on each step).

{52 \choose 7}{7 \choose 2}{45 \choose 7}{7 \choose 2}{38 \choose 7}{7 \choose 2}{31 \choose 7}{7 \choose 2}={52 \choose 7}{45 \choose 7}{38 \choose 7}{31 \choose 7}{7 \choose 2}^4

7 0
3 years ago
What’s 45 divided by -15•3<br><br> And the dot is multiplication!
Jlenok [28]

Answer:

-1

Step-by-step explanation:

45 / -15 x 3

45/ -45

-1

8 0
3 years ago
BC¯¯¯¯¯ is parallel to DE¯¯¯¯¯.
Dmitrij [34]
CE/25 = 6/15
CE = 25 * 6 / 15
CE = 10

answer
CE = 10 units
6 0
3 years ago
What is the lcm of 36 and 78
pochemuha
36|2
18|2
9|3
3|3
1

78|2
39|3
13|13
1

LCM(36,78)=2^2\cdot3^2\cdot13=468

7 0
3 years ago
Mr.Martin is giving a math test next period.The test,which is worth 100 points,has 29 problems. Each problem is worth either 5 p
blsea [12.9K]

Answer:

The second option

Step-by-step explanation:

x+y=29

5x+2y=100

then y=29–x

since 5x+2y=100

then 5x+2(29–x)=100

then 5x+58–2x=100

then 3x+58=100

then 3x=100–58

then 3x=42

then x=42/3

then x=14

then y=29–14=15

5 0
4 years ago
Read 2 more answers
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