Answer:
a) nearest jump is JL = 1380 inches = 115ft
b) number of jumps in 1 mile N= 46 jumps
Step-by-step explanation:
Given that the jump length is proportional to the body length.
If 2 inch grasshopper can jump 40 inches.
JL = k(BL)
k = JL/BL
where JL = jump length = 40 inches
BL = Body length = 2 inches.
k = 40/2 = 20
The constant of proportionality is 20.
For the athlete :
BL = 5ft 9 inches = 5(12)+9 = 69 inches.
The jump length of the athlete is:
JL = k(BL) = 20(69)
JL = 1380 inches. = 115ft
The number of jumps in 1 mile is
1 mile = 63360 inches
N = 63360/1380
N = 45.9 = 46
N= 46
Therefore, 46 jumps would be needed.
Answer:
1
Step-by-step explanation:
1/2x1x2
1
Answer:
m
Step-by-step explanation:
this makes no sense to me
Answer:
is the number of graph edges which touch v
Step-by-step explanation:
To find the degree of a graph, figure out all of the vertex degrees. The degree of the graph will be its largest vertex degree. The degree of the network is 5.
Once you know the degree of the verticies we can tell if the graph is a traversable by lookin at odd and even vertecies. First lets look how you tell if a vertex is even or odd.
Factors of -100
-1,100 or 1,-100
-2,50 or 2,-50
-4,25 or 4,-25
-5,20 or 5,-20
-10,10
now through trial and error we add these together until we get 8 which is...
none of these, are you sure that you have the correct numbers?
