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2 years ago

12

In the same amount of time, James drove twice as far as Roger. Altogether, James and Roger drove 90km. Find the number of kilome

tres driven by each person.

1 answer:

miskamm [114]2 years ago

8 0

Answer:

james drove 60 and roger drove 30

Step-by-step explanation:

90/3= 30= roger

90/3=30x2=60= james

james(60)+roger(30)= 90

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How do you take the antiderivative of (sinxcosx)^2?

gtnhenbr [62]

<span>∫(sinx cosx)^2dx = ∫(1/2sin 2x)^2 dx = 1/4∫sin^2 2x dx = 1/4∫1/2(1 - cos 4x)dx = 1/8∫(1 - cos 4x) dx = 1/8[x - sin 4x / 4] + c = 1/32(4x - sin 4x) + c
</span>

8 0

3 years ago

F(x)=2x+3 and g(x)=4x-2. Find f(x) x g(x). Find f(x) - g(x).

const2013 [10]

Answer:

<u><em>f(x) * g(x) is </em></u><u><em>8x^2 + 8x -6</em></u>

<u><em>f(x) - g(x) is </em></u><u><em>-2x + 5</em></u>

Step-by-step explanation:

<u><em>When finding the answer, we can notice they already give the values for the needed answers.</em></u>

<u><em>The first one requires f(x) and g(x). At the beginning of the question it shows that </em></u><u><em>f(x) is equal to 2x+3. Meaning we can plug in 2x+3 for f(x).</em></u>

<u><em>The same goes for g(x). At the begginning of the question, it shows that </em></u><u><em>g(x) is equal to 4x-2. Meaning we can plug in 4x-2 for g(x).</em></u>

<u><em>f(x) * g(x)</em></u>

<u><em>(2x+3) * (4x-2)</em></u>

<u><em>To find the answer, we need to </em></u><u><em>distibute the 2x+3 into 4x-2</em></u><u><em>.</em></u>

<u><em>To distribute, we do </em></u><u><em>:</em></u>

<u><em>2x * (4x-2) + 3 * (4x-2)</em></u>

<u><em>First we distribute the 2x</em></u>

<u><em>2x * 4x = 8x^2 and 2x * -2 = -4x</em></u>

<u><em>8x^2 - 4x</em></u>

<u><em>Next we distibute the 3</em></u>

<u><em>3 * 4x = 12x and 3 * -2 = -6</em></u>

<u><em>12x - 6</em></u>

<u><em>Now we can combine them by</em></u><u><em> adding like terms </em></u><u><em>to get the asnwer:</em></u>

<u><em>8x^2 = 8x^2</em></u>

<u><em>-4x + 12x = 8x</em></u>

<u><em>-6 = -6</em></u>

<u><em>The first answer is </em></u><u><em>8x^2 + 8x -6</em></u>

<u><em>Second question:</em></u>

<u><em>Since we already know the values for f(x) and g(x), all we have to do is </em></u><u><em>plug in the values</em></u><u><em>.</em></u>

<u><em>(2x+3) - (4x-2)</em></u>

<u><em>This time, since we are subtracting, all we have to do is </em></u><u><em>subtract like terms</em></u><u><em>.</em></u>

<u><em>2x - 4x = -2x</em></u>

<u><em>3 - (-2) = 5</em></u>

<u><em>The second answer is </em></u><u><em>-2x + 5</em></u>

3 0

2 years ago

5 pounds 80 cents $1.40 per pound

tensa zangetsu [6.8K]

What’s your question?

6 0

2 years ago

If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

6 0

3 years ago

A ladder is leaning against a building so that the top of the ladder is touching the roof line. The bottom of the ladder is 8 fe

Scorpion4ik [409]

Answer: 15 ft

Step-by-step explanation:

I took the test :)

4 0

2 years ago