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sleet_krkn [62]
2 years ago
11

Could you explain how to do them? i have no idea what they were called

Mathematics
1 answer:
dimaraw [331]2 years ago
3 0

Answer: See below.

Step-by-step explanation:

First table from left to right

7 12 14 11 6 8 13 12 9 15

Second table from left to right

1 9 6 12 7 8 5 9 4 3

Third table from left to right

12 33 21 15 24 36 9 27 6 18

Fourth table from left to right

2 5 9 6 12 3 8 7 11 10


Please leave mark this answer as brainliest if I helped you out :)

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A population has the following characteristics.(a) A total of 25% of the population survives the first year. Of that 25%, 75% su
zaharov [31]

Answer:

After 1st year, the age distribution will be

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

Step-by-step explanation:

A population has the following characteristics.

A total of 25% of the population survives the first year. Of that 25%, 75% survives the second year.

The average number of offspring for each member of the population is 3 the first year, 5 the second year, and 3 the third year.

From the above information, we can construct a transition age matrix.

A = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right]

The population now consists of 144 members in each of the three age classes.

From the above information, we can construct the current age matrix.

x = \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

How many members will there be in each age class in 1 year?

After 1st year, the age distribution will be

x_1 = A \cdot x

x_1 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}144\\144\\144\end{array}\right]

The matrix multiplication is possible since the number of columns of first matrix is equal to the number of rows of second matrix.

x_1 = \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

After 2nd year, the age distribution will be

x_2 = A \cdot x_1

x_2 = \left[\begin{array}{ccc}3&5&3\\0.25&0&0\\0&0.75&0\end{array}\right] \times \left[\begin{array}{ccc}1584\\36\\108\end{array}\right]

x_2 = \left[\begin{array}{ccc}5256\\396\\27\end{array}\right]

4 0
3 years ago
Lee drove 348 miles on Monday and 135 miles on Tuesday. is 313 miles a reasonable answer for how much farther Lee drove on Monda
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NO,313 IS NOT A REASONABLE ANSWER FOR HOW MANY MORE MILES LEE DROVE ON MONDAY THAN ON TUESDAY BECAUSE IF YOU SUBTRACT 135 FROM 248 YOU GET 213.
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You are saving money to buy a skateboard. You begin with $45 and you save $3 each week. The expression 45 + 3w gives the amount
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Answer:

$89

Step-by-step explanation:

45 + 3w

45 + 3•8

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$89

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Answer:

8a) 118°

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360-62-62=236

1/2 of 236 is 118

m<NPQ=118°

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