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1 year ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics

2 answers:

svetlana [45]1 year ago

5 0

Answer:

C. 314 $in^{3}$

Step-by-step explanation:

The volume of a cone is: 1/3 $\pi$ $r^{2}$ h'

1/3 x 3.14 x $5^{2}$ x 12

1/3 x 3.14 x 25 x 12

1/3 x 3.14 x 300

100 x 3.14

V = 314

kvasek [131]1 year ago

4 0

Answer:

The answer is 314

Step-by-step explanation:

You need to do

3.14(pie) times the radius times the height divided by 3

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Sherry's paycheck was $1300.00. When she cashed her check at the bank, the teller gave her a total of 25 bills, both hundreds an

serg [7]

Answer:

Step-by-step explanation:

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3 years ago

GIVING BRAINLIEST TO WHOEVER HAS A GOOD EXPLANATION AND ANSWER

Katyanochek1 [597]

Answer:

-1/5>-10/4

Step-by-step explanation:

In the negatives, If you take away the negative the lower number is more.

Think about a number line, if you are at -1/5, it means that you are 1/5 away from 0. If you are at -10/4, It means that you are 10,4 away from 0.

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2 years ago

Simplifying your answer

coldgirl [10]

Answer:

-49

Step-by-step explanation:

In order to fill in the given expression, we need to know ...

f(-2) = -4
f(-3) = 5
f(-4) = 7
g(0) = -7
g(-3) = 3

Then the expression is ...

√(5 -(-4)) -(-7)² +7÷(-7)·(3) = √9 -49 +7/(-7)(3)

= 3 -49 +(-1)(3) = 3 -49 -3

= -46 -3 = -49

7 0

3 years ago

Bianca's bank offers a savings account with a 2.1% APR, compounded monthly. What is the actual annual percentage yield on this a

Elanso [62]

2.1 x 12 = 25.2% is the percentage yield

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3 years ago

Read 2 more answers

A survey of 80 randomly selected companies asked them to report the annual income of their presidents. Assuming that incomes are

Artyom0805 [142]

Answer:

The 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

Step-by-step explanation:

The information provided is:

$n=80\\\sigma=30,000\\\bar x=585062.50\\\text{Confidence level} = 90\%$

The critical value of <em>z</em> for 90% confidence level is, 1.645.

Compute the 90% confidence interval estimate of the mean annual income of all company presidents as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\\\\=585062.50\pm 1.645\times\frac{30000}{\sqrt{80}}\\\\=585062.50\pm5517.50\\\\=(579545, 590580)$

Thus, the 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

This interval implies that there is 90% probability that the true mean annual income of all company presidents is within this interval.

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2 years ago