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KiRa [710]
3 years ago
7

Over four evenings, Ms.Cross grades 6 papers, 8 papers, 9 papers, and 7 papers. She wants to grade an average of 9 papers a nigh

t. What would be a reasonable estimate of how many papers Ms.Cross must grade on the fifth day to reach that goal?
A)11
B)15
C)18
D)19
Mathematics
1 answer:
cupoosta [38]3 years ago
7 0
The answer would be 15. The average of 6, 7, 8, 9, and 15 is 9. Hope this helps.
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Simplify: m^2n^3 aanm^2a^2n^4
dolphi86 [110]

9514 1404 393

Answer:

  a^4·m^4·n^8

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)(a^c) = a^(b+c)

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m^2n^3 aanm^2a^2n^4

= a^(1+1+2)·m^(2+2)·n^(3+1+4)

= a^4·m^4·n^8

3 0
3 years ago
Solve the equation. Check your solution. 3x - 2 = 16
DedPeter [7]
X=6

16 plus 2 is 18 and divided by 3 is 6
3 0
3 years ago
Read 2 more answers
Does this look right?
guajiro [1.7K]

Answer:

yeah

Step-by-step explanation:

its basically looks good, if your teacher gives a bad grade than idk, but looks about right :)

6 0
3 years ago
Help plz i will give brainliest
jasenka [17]

Answer:

12

(If needed explanation ask in the comments! ty)

Hope This Helps! •v•

6 0
2 years ago
The question says 5k+6k+4k=90. What does k equal?
alina1380 [7]
5k+6k+4k=90 \\ \\ 15k = 90 \ / \ simplify \\ \\ k =  \frac{90}{15} \ / \ divide \ each \ side \ by \ 15 \\ \\ k = 6 \ / \ simplify \\ \\

The final result is, k = 6.
5 0
3 years ago
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