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4 years ago

7

Over four evenings, Ms.Cross grades 6 papers, 8 papers, 9 papers, and 7 papers. She wants to grade an average of 9 papers a nigh

t. What would be a reasonable estimate of how many papers Ms.Cross must grade on the fifth day to reach that goal?
A)11
B)15
C)18
D)19

1 answer:

cupoosta [38]4 years ago

7 0

The answer would be 15. The average of 6, 7, 8, 9, and 15 is 9. Hope this helps.

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The expression 3P2 represents the number of ways of:?

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3 years ago

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Please help asap thank you

maw [93]

Answer:

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Mean:22

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3 years ago

Help me find rate change between 2 and 17

Marrrta [24]

Answer:

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3 years ago

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Sam is rowing a boat away from a dock. The graph shows the relationship

Yuki888 [10]

Answer:

After 60 minutes, Sam is 6 meters from the dock

Step-by-step explanation:

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3 years ago

disa [49]

<h3>Explanation:</h3>

There is a theorem :

$\mathbf{a^{2}-b^{2}=(a-b)(a+b)}$

Proof: open the brackets on right side of equality by using distributive property

RHS = a(a+b) - b(a+b)

RHS = $\mathrm{a^{2}+ab-ab-b^{2}}$

RHS = $\mathrm{a^{2}-b^{2}}$ = LHS

Using the above theorem you can solve every question you asked:

$\mathrm{4x^{2}-1=(2x)^{2}-1^{2}=(2x-1)(2x+1)}$
$\mathrm{9x^{2}-64=(3x)^{2}-(8)^{2}=(3x-8)(3x+8)}$

$\mathrm{49x^{2}-121=(7x)^{2}-(11)^{2}=(7x-11)(7x+11)}$

$\mathrm{4x^{2}-y^{2}=(2x)^{2}-y^{2}=(2x-y)(2x+y)}$

$\mathrm{9x^{2}-b^{2}=(3x)^{2}-b^{2}=(3x-b)(3x+b)}$

$\mathrm{16x^{2}-9b^{2}=(4x)^{2}-(3b)^{2}=(4x-3b)(4x+3b)}$

$\mathrm{x^{2}-42^{2}=(x-42)(x+42)}$

6 0

4 years ago