PLS HELPPPPP!!!!!!!!!!!!!!!!!!!! 15 POINTS
2 answers:
Answer:
y = negative 2 (x minus one-half)
Step-by-step explanation:
The equation of a line is given as:
y = mx + c, where m is the slope and c is the intercept on the y axis.
The equation of a line going through (0, 1) and (1, - 1) is calculated using:
The solution of two lines is at their point of intersection. The equation of the line that would not have any solution with y = -2x + 1 would be a line that is parallel to y = -2x + 1. Since the two lines would be parallel to each other, their would be no intersection and therefore no solution.
Two lines are said to be parallel to each other if they have the same slope. The slope of y = -2x + 1 is gotten by comparing with y = mx + c, therefore the slope m = -2. From the options the only line with a slope m = -2 is y = -2(x -1/2). Therefore y = -2(x -1/2) is parallel to y = -2x + 1 and would have no solution
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The Law of Cosines is always preferable when there's a choice. There will be two triangle angles (between 0 and 180 degrees) that share the same sine (supplementary angles) but the value of the cosine uniquely determines a triangle angle.
To find a missing side, we use the Law of Cosines when we know two sides and their included angle. We use the Law of Sines when we know another side and all the triangle angles. (We only need to know two of three to know all three, because they add to 180. There are only two degrees of freedom, to answer a different question I just did.
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The points (x,y) on the parabola are equidistant from the line to the point. Since the distances are equal so are the squared distances.
The squared distance from (x,y) to the line y=k is </span>
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The squared distance from (x,y) to (p,q) is </span>
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These are equal in a parabola:
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<span>3.There are two fruit trees located at (3,0) and (−3, 0) in the backyard plan. Maurice wants to use these two fruit trees as the focal points for an elliptical flowerbed. Johanna wants to use these two fruit trees as the focal points for some hyperbolic flowerbeds. Create the location of two vertices on the y-axis. Show your work creating the equations for both the horizontal ellipse and the horizontal hyperbola. Include the graph of both equations and the focal points on the same coordinate plane.
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The Law of Cosines is always preferable when there's a choice. There will be two triangle angles (between 0 and 180 degrees) that share the same sine (supplementary angles) but the value of the cosine uniquely determines a triangle angle.
To find a missing side, we use the Law of Cosines when we know two sides and their included angle. We use the Law of Sines when we know another side and all the triangle angles. (We only need to know two of three to know all three, because they add to 180. There are only two degrees of freedom, to answer a different question I just did.
<span>2.An archway will be constructed over a walkway. A piece of wood will need to be curved to match a parabola. Explain to Maurice how to find the equation of the parabola given the focal point and the directrix.
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We'll use the standard parabola, oriented in the usual way. In that case the directrix is a line y=k and the focus is a point (p,q).
The points (x,y) on the parabola are equidistant from the line to the point. Since the distances are equal so are the squared distances.
The squared distance from (x,y) to the line y=k is </span>
<span>
The squared distance from (x,y) to (p,q) is </span>
These are equal in a parabola:
</span>
</span>
Gotta go; more later if I can.
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