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2 years ago

Evaluate 6 ( x +2) if x = 1/2

Mathematics

1 answer:

zysi [14]2 years ago

3 0

Answer:

Step-by-step explanation:

substitute x = $\frac{1}{2}$ into the expression

6( $\frac{1}{2}$ + 2) ← multiply each term in the parenthesis by 6

= 3 + 12

= 15

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If r varies directly as w and the constant of variation is 12 what is the value of w when r =42

Airida [17]

r=kw

r=12w

42 = 12*w

divide by 12

42/12 =w

3.5 = w

5 0

3 years ago

which equation models the same quadratic relationship as function f? f(x)=x^2+12x+4 a) y=(x-6)^2+40 b) y=(x+6)^2-32 c) y=(x-6)^2

motikmotik

9514 1404 393

Answer:

b) y=(x+6)^2-32

Step-by-step explanation:

Add and subtract the square of half the x-coefficient to put into vertex form.

f(x) = x^2 +12x +4 . . . . . given

y = x^2 +12x +36 +4 -36 . . . . add and subtract (12/2)^2 = 36

y = (x +6)^2 -32 . . . . . . . . . . . write in vertex form

7 0

3 years ago

Read 2 more answers

A dozen apple costs $2.55.at this rate how much would 8 apple cost?

vladimir2022 [97]

12=2.55 how about 8
8 x 2.55 divided by 12=$1.7

8 0

3 years ago

Simplify the expression?

umka21 [38]

5b^2A^2/6 that would be the answer

7 0

3 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

Evaluate 6 ( x +2) if x = 1/2​

Evaluate 6 ( x +2) if x = 1/2