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mote1985 [20]
3 years ago
12

Simplify the expression?

Mathematics
1 answer:
umka21 [38]3 years ago
7 0
5b^2A^2/6 that would be the answer

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Colleen plans to start a small business by making and selling skirts. A sewing machine costs $250, and she estimates that she wi
Dmitrij [34]
Let C(x) be the function which calculates the total cost of making x skirts.

There is going to be a fixed constant, 250, to which we will add 15$ per x skirts.


So C(x)=250+15x

Answer: 250+15x
7 0
3 years ago
Read 2 more answers
Find the value of (-4)(6)(-7)<br> -178<br> 168<br> 178<br> -168
kakasveta [241]

<u><em>Answer:</em></u>

168

<u><em>Explanation:</em></u>

<u>Before we begin, remember the following:</u>

+ve * +ve = +ve                     -ve * -ve = +ve

+ve * -ve = -ve                       -ve * +ve = +ve

<u>Now, for the given problem we have:</u>

(-4) * (6) * (-7)

<u>Let's take the first two terms:</u>

(-4) * (6)

Based on the above rules, the product will be negative

<u>Therefore, </u>

(-4) * (6) = -24

<u>Now, the expression became:</u>

(-24) * (-7)

Again, based on the above rule, the product here will be positive

<u>Therefore,</u>

(-24) * (-7) = 168

Hope this helps :)

4 0
3 years ago
Read 2 more answers
The 4 in 400,000 has a value of 400 yes or no
Oduvanchick [21]

I'm pretty sure its not.

8 0
3 years ago
Read 2 more answers
What you use an area model how can you tell if two fractions are not equivalent
svp [43]

Answer:

multiply or  simplify

Step-by-step explanation:

8 0
3 years ago
For what values of x is log base 0.8 (x+4)&gt;log base 0.4 (x+4)<br>Thank you!
Radda [10]
We are seeking the solution of the inequality:

\displaystyle{ \log_{0.8}(x+4)\ \textgreater \ \log_{0.4}(x+4).


We recall that a log function f(x)=\log_b(x) is either increasing or decreasing:

i) it is increasing if b>1, 

ii) it is decreasing if 0<b<1.

Consider the functions \displaystyle{ \log_{0.8}(x) and \displaystyle{ \log_{0.4}(x).

The graphs of these functions both meet at x=1 (clearly), and after 1 they are both negative. So from 0 to 1 one of them is larger for all x, and from 1 to infinity the other is larger. (Being strictly decreasing, their graphs can only intersect once.)


We can check for a certain convenient point, for example x=0.8:

\displaystyle{ \log_{0.8}(0.8)=1 and

\displaystyle{ \log_{0.4}(0.8)=\log_{0.4}(0.4\cdot 2)=\log_{0.4}(0.4)+\log_{0.4}(\cdot 2)=1+\log_{0.4}(2).

Now, \displaystyle{ \log_{0.4}(2) is negative since we already explained that for x>1 both functions were negative. This means that 

\displaystyle{ \log_{0.8}(0.8)\ \textgreater \ \log_{0.4}(0.8), and since 0.8\in (0, 1), then this is the interval where \displaystyle{ \log_{0.8}(x)\ \textgreater \ \log_{0.4}(x).


So, now considering the functions \displaystyle{ \log_{0.8}(x+4) and \displaystyle{ \log_{0.4}(x+4), we see that 

x+4 must be in the interval (0,1), so we solve:

0<x+4<1, which yields -4<x<-3 after we subtract by 4.


Answer: (-4, -3). Attached is the graph generated using Desmos.

7 0
3 years ago
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