Answer:
Your answer is
Congruent means similar.
Other angle is 69°
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Answer:
between 3 and 4
Step-by-step explanation:
to find 19/6 located where on the number line
first we need to convert 19/6 to decimal
19/6 = 3.166...
so lets now see where 3.166 lies
it first lies between 3.160 and 3.170
but we need integer
so we go deeper and see
it lies between 3.100 and 3.200
and then we need to go more deeper to get an integer not decimal
now it lies between 3 and 4
Answer:
320 calories
Step-by-step explanation:
1/4 would be 80 calories because 70 is ten less so it would be 80 = 1/4 so 80 times 4 would be 320 calories
Answer:
x + 1
Step-by-step explanation:
There are a few ways this problem could be solved. The easiest route is to note that the first part of the question says "2 consecutive numbers". If the numbers are next to each other on a number line (consecutive) and x is the smaller number, the larger number is x + 1.
To check, let's find the two numbers. We know the numbers are next to each other on a number line and that together, they equal 37. Let's begin with 15 and 16.
15 + 16 = 31
These numbers are too low, as they should add to 37. Let's try 18 and 19.
18 + 19 = 37
There are the two correct numbers. If x = the smaller number, x = 18.
18 + 1 = 19
Since this is correct, we know for sure that the answer is x + 1.
![\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{64}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{0\qquad \textit{from the ground}}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%5Ctextit%7Binitial%20velocity%7D%20%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7Bllll%7D%20~~~~~~%5Ctextit%7Bin%20feet%7D%20%5C%5C%5C%5C%20h%28t%29%20%3D%20-16t%5E2%2Bv_ot%2Bh_o%20%5Cend%7Barray%7D%20%5Cquad%20%5Cbegin%7Bcases%7D%20v_o%3D%5Cstackrel%7B64%7D%7B%5Ctextit%7Binitial%20velocity%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h_o%3D%5Cstackrel%7B0%5Cqquad%20%5Ctextit%7Bfrom%20the%20ground%7D%7D%7B%5Ctextit%7Binitial%20height%20of%20the%20object%7D%7D%5C%5C%5C%5C%20h%3D%5Cstackrel%7B%7D%7B%5Ctextit%7Bheight%20of%20the%20object%20at%20%22t%22%20seconds%7D%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D)
Check the picture below, it hits the ground at 0 feet, where it came from, the ground, and when it came back down.
