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2 years ago

What are the parts of an algebraic expression, and how do they relate to polynomial expressions?

Mathematics

1 answer:

Arlecino [84]2 years ago

3 0

The parts of algebraic expressions related to polynomials are variables and coefficients.

<h3>What are the parts of algebraic expressions?</h3>

The parts of algebraic expressions are;

Variables which are letters that represent numbers
Coefficients are numbers that multiply the variables
Constant is a number that is not multiplied by any variable

Polynomials are algebraic expressions composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, and multiplication

Polynomials consists of variables and coefficients. The variables in polynomials are also called indeterminates. The coefficients also multiply this variables.

Thus, the parts of algebraic expressions related to polynomials are variables and coefficients.

Learn more about algebraic expressions here:

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jeds market has a total of 26 employees. Each full time employee makes $275/ week, and each part-time employee makes $140/ week.

ollegr [7]

The number of full time employees is 17 and the number of part time employee is 9

Step-by-step explanation:

Step 1 :

Let f represent the number of full time employee and p represent the number of part time employee

Total number of employees = 26

Hence we have f + p = 26

Step 2 :

Wages of full time employee = $275

Wages of part time employee = $140

Total wages paid by Jeds = $ 5935

Hence we have 275 f + 140 p = 5935

Step 3:

Solving the equations obtained in step 1 and step 2 we have

f + p = 26, Multiplying by 275 = > 275 f + 275 p = 7150

275 f + 140 p = 5935

Subtracting equation 2 from 1 we have

135 p = 1215 => p = 9

Substituting this in f + p = 26 gives, f + 9 = 26

So f = 17

Step 4 :

Answer :

The number of full time employees is 17 and the number of part time employee is 9

5 0

3 years ago

Determine 3rd term in the geometric sequence whose first term is -8 and whose common ratio is 6

Brrunno [24]

-8, -48, -288
or
-8, -4/3, -2/9

3 0

3 years ago

Read 2 more answers

Is the statement true or false? If false, give a counterexample.

scoundrel [369]

Answer:

D. false; if a = 1, b = 2, and c = 3, then 1(2 + 3) ≠ 1(2) + 2(3)

Step-by-step explanation:

A is false, because the a is being distributed/ being multiplied to all terms inside the parenthesis, and not the term b.

B is also false. There is no indicated negative signs.

C is also false because 1(1 + 1) is EQUAL to 1(1) + 1(1)

D is true.

6 0

3 years ago

Which gives 28 + 24 as a product of the GCF and a sum?

VashaNatasha [74]

Answer:

b. 4 (7 + 6)

Step-by-step explanation:

Finding the GCF between 28 and 24:

We keep dividing while both numbers can be divided by the same factor. So

28 - 24|2

14 - 12|2

7 - 6

There is no number for which 7 and 6 are both divisible by, so the GCF between 28 and 24 is 4.

Simplifying in function of the GCF:

Now, we put 4 in evidence, and divide the rest of the expression by 4. So

$28 + 24 = 4(\frac{28}{4} + \frac{24}{4}) = 4(7 + 6)$

The answer is given by option b.

7 0

3 years ago

Imagine you are standing near a large rectangular pool and your friend asks you how far you think it is from one corner of the p

pickupchik [31]

Answer:

See explanation below.

Step-by-step explanation:

A right triangle is a triangle that has a right angle (90º). In math, the Pythagorean theorem allows us to calculate the length of the sides of a right triangle.

In a right triangle, the legs are the two sides that meet at the 90º angle and the hypotenuse is the side that opposes the right angle. The Pythagorean Theorem tells us that the square of the hypotenuse equals the sum of the squares of the legs. In other words: $c^2 =a^2 +b^2$ where c is the hypotenuse and a and b are the legs.

Now, we can use this formula to calculate the diagonal of the pool if we just have the length and the width (these would be the legs of the triangle). We need to measure both the length and the width and then square both of them and sum up the squares: this would give us the square of the diagonal so we will only need to find its quadratic root and we will have the length of the diagonal.

For example, let's say we have a pool that is 3 ft by 4ft, using the formula we have:

$Diagonal^2=3^2 +4^2 \\Diagonal^2 = 9+16\\Diagonal^2 = 25\\Diagonal = \sqrt{25} \\Diagonal =5$

Therefore, in this case the diagonal would be 5 ft long.

5 0

3 years ago