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3 years ago

Help me answer this thanks

Mathematics

1 answer:

vodka [1.7K]3 years ago

8 0

Answer: side c is 20!

Step-by-step explanation:

So since this a right-angled triangle, you might want to use the Pythagorean Theorem. First, use the formula A(squared) + B(squared) + C(squared). Since c is unknown just put that as x(squared). Then, answer A(squared) and B(squared which would be 16mm and 12mm in this case. Multiply 16*16.... and you get 256. Then do the same to side B which is 12 and you get 144. Then know you can add them both together and get 400. What is the square root of 400? Yes, it’s 20. And there is you answer!

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Tommy was solving the triangle below. Which of the following is TRUE about his solution? Help ASAP !!!!

Mademuasel [1]

Answer:

The value of x is incorrect he should be using 28/21 instead of 21/28

Step-by-step explanation:

tan = opp/adj

tanx = 28/21

The value of x is incorrect he should be using 28/21 instead of 21/28

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2 years ago

Read 2 more answers

How do you find the area of a circle with the circumference?

Naya [18.7K]

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3 years ago

Why are details imporant?

pshichka [43]

Answer:

Step-by-step explanation:

Details are important because they are like pieces of a puzzle, they all work together to create the bigger picture.

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3 years ago

Factorise fully 6ac + 10ac

ikadub [295]

Step-by-step explanation:

6ac+10ac

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3 years ago

The following statement is either true (in all cases) or false (for at least one example). If false, construct a specific e

matrenka [14]

Answer:

False, counterexample below

Step-by-step explanation:

Denote the unit vectors of R^3 by $e_1=(1,0,0), e_2=(0,1,0), e_3=(0,0,1)$ . Now consider $v_1=e_1, v_2=2e_1$ and $v_3=e_3$ . We have that $v_1, v_2,v_3 \in \mathbb{R}^3$ . Also, the vector $v_3$ is not a linear combination of $v_1, v_2$ because any linear combination of these two vectors will have third coordinate zero, but v_3 has third coordinate 1 so they can't be equal.

However, the set $\{v_1, v_2,v_3\}$ is not linearly independent, because $2v_1-v_2+0v_3=0$ is a non-trivial linear combination of these vectors that equals zero.

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3 years ago