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ruslelena [56]
1 year ago
5

Find the volume of these solid20mm3.7mm41mm​

Mathematics
1 answer:
Reil [10]1 year ago
8 0

The volume of the solid is which is a cone is 100.48 km^{3}.

Given a cone of radius 4 km and height being 6 km.

We are told to find the volume of the cone.

Volume is basically the amount of a substance that a container can hold in its capacity.Its value cannot be equal to zero or negative. It is basically amount of filling in a container.

Volume of cone is 1/3 \pi r^{2} h.

Volume =1/3 \pi 4^{2} *6

=1/3 π*16*6

=32π

=32*3.14

=100.48km^{3}

Hence if the radius of the cone is 4 km and height be 6 km then the volume of the cone is 100.48km^{3}.

Learn more about volume at brainly.com/question/463363

#SPJ1

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5 0
2 years ago
After 3 hours, Ernie had travelled 195 miles. If he travels at a constant speed, how far will he have
Umnica [9.8K]

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x = 325 miles

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7 0
2 years ago
A vertical right circular cylindrical tank has height h=8 feet high and diameter d=6 feet. It is full of kerosene weighing 50 po
Mariana [72]

Answer:

The work done to  pump all of the kerosene from the tank to an outlet is W=45238.9\: J  

Step-by-step explanation:

The work is defined by:

W=\int dFdx (1)    

The force here will be the product between the volume and the kerosene weighing, so we have :

dF=\pi R^{2}dy*50

This force will be in-lbs.

Where R is the radius (3 feet)                    

Then using (1), we have:

W=\int \pi R^{2}dy*50(8-y)  

Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.

W=\int_{0}^{8} \pi 3^{2}dy*50(8-y)

W=450\pi \int_{0}^{8}dy(8-y)

W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)

W=450\pi(8y|_{0}^{8} -\frac{y^{2}}{2}|_{0}^{8})  

W=450\pi(8*8 -\frac{8^{2}}{2})

W=450\pi(64 -\frac{64}{2})

Therefore, the work done to  pump all of the kerosene from the tank to an outlet is W=45238.9\: J  

I hope it helps you!  

6 0
3 years ago
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