See the attached figure.
========================
AB = 10 , FD = 3
∵ D is the midpoint of AB, and F is the mid point of CB
∴ FD // AC , FD = 0.5 AC
∵ Δ ABC is a right triangle at C
∴ FD ⊥ BC
∴ BD = 0.5 AB = 5
∴ in Δ FDB ⇒⇒ BF² = BD² - FD² = 5² - 3² = 16
∴ BF = √16 = 4
∵ F is the mid point of CB
∴ CF = BF = 4 , and CB = 2 BF = 2*4 = 8
∵ D is the midpoint of AB, and E is the mid point of AC
∴ DE // CB , and DE = 0.5 CB = 0.5 * 8 = 4
∴ T<span>he length of line ED is 4
</span>
Answer:
28 times
Step-by-step explanation:
On a fair die, the probability of rolling a 6, the only number greater than 5, is 1/6. So in 168 rolls of this die, Malachy can expect a 6 on 1/6 × 168, or 28 times.
Answer:
the answer is 3 and 9. 9 is 6 greater than 3 and 9 squared and 3 squared added up give you 90.
The answer is [ ∠A ≅ ∠A; A F/AB = AG/AC = 3 ]
Both triangles are the same just different sizes.
The length of A F is 9 units. The length of AB is 3 units.
To find the scale factor, just divide.
9 / 3 = 3
The length of AG is 6 units. The length of AC is 2 units.
To find the scale factor, just divide.
6 / 2 = 3
The only logical answer is B because the ratio's are written to where when you solve them, you get the scale factor 3.
Best of Luck!
Answer:
2⋅2⋅2⋅5=40 2 ⋅ 2 ⋅ 2 ⋅ 5 = 40