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densk [106]
1 year ago
11

Chris, nina, and iana each have a 3/4 chance of going to cafe shirley for an afternoon coffee at 1:00pm. jeffrey will only go to

cafe shirley for a coffee if at least one of his friends is at the cafe. what is the probability that jeffrey goes to cafe shirley for a coffee today?
Mathematics
1 answer:
Zielflug [23.3K]1 year ago
4 0

Answer:

Jeffrey has 225 % chance to go to Cafe Shirley.

Step-by-step explanation:

given,

chance of going to Cafe

Chris = 3/4

Nina =3/4

iana = 3/4

To find the total probability you should add all of them:

Total probability= 3/4 + 3/4 + 3/4

= 9/4 = 2.25

to convert to percent you should times 100

2.25 x 100 = 225%//

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Step-by-step explanation:

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3 years ago
2/7 • 9 1/10<br> Please help
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3 0
3 years ago
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The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

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P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
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Zina [86]

Answer:

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4 0
3 years ago
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