Answer:r'=0.327 m
Step-by-step explanation:
Given
angular velocity 
mass of objects 
distance of objects from stool 
Combined moment of inertia of stool and student 
Now student pull off his hands so as to increase its speed to 3.60 rev/s
Initial moment of inertia of two masses 
After Pulling off hands so that r' is the distance of masses from stool
Conserving angular momentum
Combine the two equations in the right amounts to eliminate y :
-2 (2x + 3y) + (3x + 6y) = -2 (17) + 30
-4x - 6y + 3x + 6y = -34 + 30
-x = -4
x = 4
Solve for y :
2x + 3y = 17
8 + 3y = 17
3y = 9
y = 3
Answer:
x=2
Step-by-step explanation:
When you sub in these values for the pythagorean theorem you get 1.5^2+x^2=2.5^2
2.25+x^2=6.25
4=x^2
x=2
The answer would be -13/3
Answer:
Step-by-step explanation:
4x+8 27
L-------------M-------------------------N
<------------------ 6x -------------------->
LM = 4x+8
MN = 27
LN = 6x
LM + MN = LN
4x+8 + 27 = 6x
35 = 2x
17.5 = x
LN = 6x = 6(17.5) = 105
