Answer:
The correct options are;
Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B
City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A
Step-by-step explanation:
Here we have for City A
Maximum - Minimum = 10
Interquartile range =3
City B
Maximum - Minimum = 18.5
Interquartile range =9.5
Therefore, City A is likely to have temperatures that remain fairly constant all year round because it has a compact interquartile range compared to that of City B
City B is likely to have more extreme temperatures with colder days in the winter and hotter days in the summer because the range is greater than that of A.
The IQR tells you how spread out the "middle" values are. It can also be used to figure out if there are any outliers.
Answer:
8/17 and 9/17
Step-by-step explanation:
8:9
both add up to 17
so it can be 8/17 or 9 but it cannot be simplified unless if you want them both as a mixed number which is
8/17 as a mixed number is 2 1/17
9/17 as a mixed number is 1 8/17
Answer:
I think 7
Step-by-step explanation:
4 , 8 , 9 and 12 has factors.
7 has no factor.
4= 2×2
8= 2×4
9= 3×3
12= 3×4
Answer:
Step-by-step explanation:
In order to write the series using the summation notation, first we need to find the nth term of the sequence formed. The sequence generated by the series is an arithmetic sequence as shown;
4, 8, 12, 16, 20...80
The nth term of an arithmetic sequence is expressed as Tn = a +(n-1)d
a is the first term = 4
d is the common difference = 21-8 = 8-4 = 4
n is the number of terms
On substituting, Tn = 4+(n-1)4
Tn = 4+4n-4
Tn = 4n
The nth term of the series is 4n.
Since the last term is 80, L = 4n
80 = 4n
n = 80/4
n = 20
This shows that the total number of terms in the sequence is 20
According to the series given 4 + 8 + 12 + 16 + 20+ . . . + 80
, we are to take the sum of the first 20terms of the sequence. Using summation notation;
4 + 8 + 12 + 16 + 20+ . . . + 80 =
