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Fed [463]
3 years ago
15

Find the zeros of the polynomial function and state the multiplicity of each.

Mathematics
1 answer:
zheka24 [161]3 years ago
7 0
\bf f(x) = 4(x + 7)^2(x - 7)^3\implies 0 = 4(x + 7)^2(x - 7)^3
\\\\\\
0=(x+7)^2(x-7)^3\implies 
\begin{cases}
0=(x+7)^7\\
\qquad 0=(x+7)(x+7)\\
\qquad -7=x\\
\qquad -7=x\\
----------\\
0=(x-7)^3\\
\qquad 0=(x-7)(x-7)(x-7)\\
\qquad 7=x\\
\qquad 7=x\\
\qquad 7=x
\end{cases}

the -7 is found there twice, so it has a multiplicity of 2
the +7 is there thrice, so it has multiplicity of 3
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7 0
3 years ago
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Please help me answer this question
lbvjy [14]

A. Let s be the smallest integer
B. We must add 2 to get the next greater integer
C. Second integer is s+2
D. s+(s+2)=118
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7 0
3 years ago
What’s the answer 6x=4x+140
dmitriy555 [2]
1) given 6x = 4x + 140

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6 0
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Is (3,-1) a solution of this system: y=2-x 3-2y=2x
I am Lyosha [343]
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8 0
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