As shown in the question, the translation changes the points as follows:

Therefore:
Answer:
Between 3 P.M. and 3:30 P.M the hour hand moves 15°.
Step-by-step explanation:
The rotation of the minute hand of a clock between 3 P.M. and 3:30 P.M. is from the the 12 hour mark to the 6 hour mark which is half of one complete cycle
One complete cycle of clock rotation = 360° = 12 hours
Therefore, the hour hand rotates 360/12 = 30° for each hour
Given that the time between 3 P.M. and 3:30 P.M. is 30 minutes = 1/2 an hour
The rotation of the hour hand between 3 P.M. and 3:30 P.M = Half the rotation for 1 hour
∴ The rotation of the hour hand between 3 P.M. and 3:30 P.M = 30°/2 = 15°
Between 3 P.M. and 3:30 P.M the hour hand moves 15°.
A 99% confidence interval for the population mean of high school students that take the bus to school every day is b) ci=(44.34%, 54.43%)
We need to find the 99% confidence interval for the population mean of high school students that take the bus to school everyday
A confidence interval is a range of estimates for an unknown parameter. The confidence interval is calculated at the specified confidence level; the most common is the 95% confidence level, but sometimes other levels are used, such as 90% or 99%.
The confidence interval of proportions is given by:
π ± z √(π (1-π) /n)
π is the sample proportion.
z is the critical value.
n is the sample size.
For 99% confidence interval the value of z is 2.58
π = 321/650
The confidence interval is given by
=321/650 ± 2.58 √( (321/650) × [ 1 - (321/650) ] ÷ 650)
= (0.493846 ± 0.050594)
=(0.4434 , 0.5443)
=(44.34 % , 54.43 %)
Hence a 99% confidence interval for the population mean of high school students that take the bus to school every day is ci=(44.34%, 54.43%)
<u>Learn more about confidence interval:</u>
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# SPJ4
Answer:
Step-by-step explanation:
h = -5t^2 - 6t + 44
I'll assume 0 meters is the ground height. That would mean we want to know the time, t, for h to be = 0 meters:
h = -5t^2 - 6t + 44
0 = -5t^2 - 6t + 44
5t^2 + 6t -44 = 0
Solve using the quadratic equation: 2.43 and - 3.63 seconds. We'll use the positive value: 2.43 seconds for the ball to reach the ground. Save the -3.63 value for the Klingons.
We can also solve by graphing the function, as per the attached image. Note that the starting time of 0 seconds, the ball is at 44 feet. It reaches the x axis at 2.43 seconds (where x = 0, the ground).
Answer:
x=8
Step-by-step explanation:
if i read your description correctly, the square root of 64 is 8.