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3 years ago

8

The formula P = ns gives the formula for the perimeter of a regular polygon with n sides and side length s. A regular hexagon ha

s 6 equal sides. What is the perimeter of a regular hexagon with side length 2.8 cm?

1 answer:

Effectus [21]3 years ago

5 0

Your answer is 16.8.

Hope this helps

Happy Holidays.

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Please Help!!! WILL GIVE BRAINLIEST!!!

kompoz [17]

Answer:

The correct statements are:

A) This polynomial has a degree of 2, so the equation $x^{2} + 4x + 4$ has exactly two roots.

B: The quadratic equation $x^{2} + 4x + 4$ has one real solution, x=−2, and therefore has one real root with a multiplicity of 2.

Step-by-step explanation:

Here, the given polynomial is $f(x) = x^{2} + 4x + 4$

FUNDAMENTAL THEOREM OF ALGEBRA:

If P(x) is a polynomial of degree n ≥ 1, then P(x) = 0 has exactly n roots, including multiple and complex roots.

Now, here the given polynomial is a quadratic polynomial with degree 2.

So, by the fundamental theorem, f(x) has EXACTLY 2 roots including multiple and complex roots.

Now, solving the equation , we get that the only possible roots of the polynomial p(x) is x = -2 and x = -2

So, f(x) has only one distinct root x = -2 with a multiplicity 2.

Hence, the correct statements are:

A) This polynomial has a degree of 2, so the equation $x^{2} + 4x + 4$ has exactly two roots.

B: The quadratic equation $x^{2} + 4x + 4$ has one real solution, x=−2, and therefore has one real root with a multiplicity of 2.

4 0

3 years ago

Please help on two math questions. I don’t understand how to do them.

Sidana [21]

When you represent intervals on the number line, you're including full dots, excluding empty dots, and you're considering numbers highlighted by the line.

In the first case, you've highlighted everything before -2 (full dot, thus included), and everything after 1 (empty dot, excluded). So, the set would be

$x\leq -2 \lor\ x>1$

or, in interval notation,

$(-\infty,-2]\cup (1,\infty)$

In the second case, you are looking for all numbers between -3 and 5. This interval is symmetric with respect to 1: you're considering all numbers that are at most 4 units away from 1, both to the left and to the right.

This means that the difference between your numbers at 1 must be at most 4, which is modelled by

$|x-1|\leq 4$

where the absolute values guarantees that you'll pick numbers to the left and to the right of 1.

3 0

3 years ago

Find the missing value of the direct variation (2,5) (5,y)

Karolina [17]

Answer:

The missing value y=12.5 and we have (5,12.5)

Step-by-step explanation:

The formula used for direct variation is:

$y\: \alpha \:x\\y=kx$

We need to find missing value (2,5)(5,y)

First we will find k, and then y

We have x=2, y=5

Find k:

$y=kx\\5=k(2)\\k=\frac{5}{2}\\k=2.5$

Now, we cam find missing value in (5,y)

We have x=5, k=2.5 and y=?

$y=kx\\y=2.5(5)\\y=12.5$

So, the missing value y=12.5 and we have (5,12.5)

7 0

3 years ago

The graph of a linear function passes through the points (2, 4) and (8, 10).

Keith_Richards [23]

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ 2}}\quad ,&{{ 4}})\quad 
% (c,d)
&({{ 8}}\quad ,&{{ 10}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{10-4}{8-2}$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\qquad 
\begin{array}{llll}
\textit{plug in the values for }
\begin{cases}
y_1=4\\
x_1=2\\
m=\boxed{?}
\end{cases}\\
\textit{and solve for "y"}
\end{array}$

8 0

3 years ago

Simplify <br> 2x x y x 3

nikitadnepr [17]

Which is it
2x times y times 3 = 6xy
or,
2xxyx3= 6x^3y

7 0

3 years ago