1297 grams of ore are needed to obtain 454.0 grams of Fe.
As the iron ore sample if found to be 35 percentage by mass
It means 35g of iron is present in 100g of ore.
1g of iron is present in 100/35 g of ore
And 454.0 g of iron is present in 100 × 454 / 35
= 1297.14 or 1297 grams (approx.)
The mass percent is calculated by dividing the mass of the compound or solute by the mass of the element or solute. A percent is obtained by multiplying the result by 100.
The formula for an element's percentage in a compound is as follows:
mass percent is calculated by multiplying the mass of the element in one mole of the compound by one hundred.
A solution follows this formula:
(gm of solute / gm of solute plus solvent) × 100 equals mass percent.
or
(gm of solute/grams of solution) x 100 Equals mass percent
Hence, 1297 grams of ore are needed to obtain 454.0 grams of Fe.
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