It could get bigger or it could have something a lot different to it than anything else
<u>Answer:</u>
5
<u>Explanation:</u>
We know that,
number of count of cardinals = 75; and
measured area = 15 square kilometers.
To find the population density of the cardinals in an area of 15 square kilometers, we need to divide the number of cardinals by the given unit area:
Population density of cardinals = 75 / 15 = 5
Therefore, the population density of cardinals in an area measuring 15 square kilometers is 5.
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Aufbau violation:
4s ↑↓ 3d ↑↓ ↑↓ ↑↓ ↑↓ ↑↓ 5s ↑
<span>3s ↑ 3p ↑ ↑ ↑ </span>
<span>Hund violation: </span>
<span>4s ↑↓ 3d ↑↓ ↑ ↓ ↑ ↑ </span>
3s ↑↓ 3p ↑↓ ↑↓
Pauli violation
<span>2s ↑↑ 2p ↑ ↑ ↑</span>
Answer: 5 moles of NaF would be produced when 550 grams of Sodium bromide are used.
Explanation:
From the question, the balanced chemical formula is illustrated below:
2NaBr + CaF2 → 2NaF + CaBr2
From the equation above;
Molecular mass of NaBr = 23 + 80 = 103g/ mol
Molecular mass of CaF2= 40+ (19×2)= 78g/ mol
Molecular mass of NaF = 23+19 = 42g/ mol
From the balanced chemical equation;
2 moles of NaBr reacted with 1mole of CaF to give 2 moles of NaF.
That is, 2 moles of NaBr= 2× 103 = 206g
2moles of NaF = 2×42= 84g
If 206g of NaBr yielded 84g of NaF
Therefore 550g of NaBr will yield Xg of NaF
X= 550×84/206
X= 224.27g of NaF
But 42g = 1 mole of NaF
Therefore 224.27g = X mole of NaF
X= 224.27 ×1/42
X is approximately 5moles.
Answer:
Empirical formula
C3H2Cl
Molecular formula
C6H4Cl2
Explanation:
Firstly, we can get the mass of carbon and hydrogen produced by calculating their number of moles from that of carbon iv oxide and water respectively.
To get the number of moles of carbon iv oxide, we simply make a division. The number of moles is the mass of carbon iv oxide divided by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol. The number of moles is thus 3.02/44 = 0.069
One atom of carbon is present in Carbon iv oxide. This means 0.069 moles of carbon is present. The mass of carbon present equals the atomic mass of carbon multiplied by the number of moles = 0.069 * 12 = 0.83g
The mass of water is 0.412g, the number of moles is 0.412/18 = 0.023
In water, there are two atoms of hydrogen. Hence the number of moles of hydrogen is 2 * 0.023 = 0.046
The mass of hydrogen is the number of moles of hydrogen multiplied by the atomic mass unit of hydrogen = 0.046 * 1 = 0.046g
Now we need to know the mass of chlorine. We simply subtract the masses of hydrogen and carbon.
1.68-0.046-0.83 = 0.804
Now we proceed to calculate the empirical formula. We simply divide the mass of each by their atomic masses and then proceed from there.
H = 0.046/1 = 0.046
C = 0.83/12 = 0.069
Cl = 0.804/35.5 = 0.023
We divide by the smallest number which is that of that of carbon
H = 0.046/0.023= 2
C = 0.069/0.023= 3
Cl = 0.023/0.023 = 1
The empirical formula would thus be C3H2Cl
The molecular formula can be calculated using the molar mass;
(C3H2Cl)n = 147
(36+ 2 + 35.5 ) = 147
73.5n = 147
n = 147/73.5 = 2
The molecular formula is thus C6H4Cl2