Molar Mass of KCLO3
= 39 + 35.5 + 48 g
= 122.5 g .
So , percentage of Potassium ( K )
= 39 / 122.5 * 100 %
= 31.83 %
Now , percentage of Chlorine ( Cl )
= 35.5 / 122.5 * 100 %
= 28.97 %
So, finally, percentage of Oxygen ( O )
= 48 / 122.5 * 100 %
= 39.18 %
Answer:
i am very sorry i have no answer but if i get one i can tell u the answer
Explanation:
The answer would be 20% (B)
