Answer:
Step-by-step explanation:
you just need to add both equations
you will get 3y=12+6=18
3y=18
y=6
now replace y=6
3x+12=6
3x=6-12
3x=-6
x=-2
(-2,6)
You know two lines y=ax+b and y=mx+n that are perpendicular, so we have the product a*m=-1
+ This line is perpendicular to y=13x-5, so it has equation: y=-1/13x+b
+ And it passes through the point (3;1), so we have x=3, y=1. So 1=-1/13 *3+b
and b= 1+3/13= 16/13
And we have y=-1/13x+16/13
Have fun
Answer:
Step-by-step explanation:
please note -2 is not a zero ,it should be 2 is a zero.
by synthetic division
2| 1 4 -10 -4
| 2 12 4
|----------------
1 6 2 | 0
x²+6x+2=0

X>7
https://quickmath.com/webMathematica3/quickmath/inequalities/solve/basic.jsp#c=solve_stepssolveinequ...
Yes. They are all correct. Good job