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alina1380 [7]
3 years ago
7

21 billion as how much more than 9.8 billion write it in scientific notation

Mathematics
2 answers:
Makovka662 [10]3 years ago
6 0

Answer:

life..........

bud

Step-by-step explanation:

Crazy boy [7]3 years ago
4 0
21 000 000 000-9 800 000 000=11 200 000 000= 1.12x10^10
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A spinner with 6 equally sized sliced has 2 blue slices 1 yellow slice and e red slices the dial is and stops on a slice at rand
Nutka1998 [239]
1/3 would be the answer
6 0
2 years ago
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What is the lateral surface area of the square pyramid below?
den301095 [7]

Answer:

lateral surface area = 48 inches²

Step-by-step explanation:

The picture below is the square base pyramid you are referring. The lateral area is adding the area of the 4 triangles in the pyramid.

area of a triangle = 1/2 × b × h

The slant height of the triangle is gotten using Pythagoras theorem

lateral surface area = 4 × (1/2 ×  3 × 8)

lateral surface area = 4 × 24/2

lateral surface area = 4 × 12

lateral surface area = 48 inches²

3 0
3 years ago
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Find the arc length. Round the answer to two decimal places.
bagirrra123 [75]

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372.233

heart if it helped brain if im cool

7 0
3 years ago
The equation of a line is<br> -2x+5t=-20 <br>what is the x-intercept of the line?
vampirchik [111]

The x intercept of the line is at x = 10.

The x intercept is always the value of x when all other values are equal to 0. So in this case, we put 0 in for t and then solve.

-2x + 5t = -20

-2x + 5(0) = -20

-2x = -20

x = 10

8 0
3 years ago
What to write it here
Orlov [11]

Answer:

84 degrees

Step-by-step explanation:

Angle A = 83 degrees

Angle B = x degrees

Angle C = 135 degrees

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We know that the four inner corners of a quadrilateral should add up to 360 degrees. Two supplementary angles will add up to 180 degrees. Adjacent angles on a straight line will always be supplementary. Knowing this, just solve for <ADC and add that amount to <A and <C. Then, subtract that sum from 360 degrees.

<ADC = 180-122 = 58

58+83+135 = 276

360-276 = 84 degrees

7 0
2 years ago
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