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zvonat [6]
2 years ago
8

Jessica's dog weighed 91.5 pounds at the beginning of summer but lost 5.2

Mathematics
1 answer:
docker41 [41]2 years ago
4 0

Answer:

91.5 - 5.2 = 86.3

Step-by-step explanation:

The initial weight was 91.5 pounds.

The dog lost 5.2 pounds which means subtraction.

91.5 pounds subtracted by 5.2 pounds that the dog lost equals 86.3 pounds.

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What is the midpoint of the x-intercepts of f(x) = (x – 4)(x + 4)? (0,0) (0,4) (–4,0) (2,0)
forsale [732]

Answer:

The midpoint of the x-intercepts of the function is (0, 0)

Step-by-step explanation:

Notice that since the function comes in factor form, we know that its roots (which are actually the intercepts the function has with the x-axis) are: x = 4 and x = -4 (the x-values for which the function renders zero).

These two points are equidistant from the origin of coordinates (0, 0), and therefore the midpoint of these x-intercepts is (0, 0).

6 0
3 years ago
Using the answers from z^4=16 determine the solutions of the equation (x+1)^4=16(x-1)^4​
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i hope i have been useful buddy.

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3 years ago
A plane lamina with constant density p(x, y) = p occupies a region in the xy-plane bounded by a simple closed path C. Show that
stira [4]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

8 0
4 years ago
How to do 14-17.. or just give me the answer .​
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3 years ago
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Anna007 [38]

h(-3) - h( - 2) = -  \frac{5}{  8} \\ \\

Step-by-step explanation:

\boxed{h(x) =  \frac{2 {x}^{2}  - x + 1}{3x - 2}}

h(2) =  \frac{2 {(2)}^{2}  - (2) + 1}{3(2) - 2}

h(2) =  \frac{2 {(4)}  - 2 + 1}{6 - 2}

h(2) =  \frac{ 8  - 1}{4}

h(2) =  \frac{7}{4}

h( - 3) =  \frac{2 {( - 3)}^{2}  - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) =  \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) =  \frac{18 + 4}{ - 11} \\ h( - 3) =    \frac{22}{  - 11} \\ h(-3) = -2

h( - 2) =  \frac{2 {( - 2)}^{2}  - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) =  \frac{2 (4)  +  2+ 1}{- 6 - 2} \\ h( - 2) =  \frac{8 +  3}{- 8} \\ h( - 2) =  \frac{11}{- 8}

h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8}

5 0
3 years ago
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