The number of presale tickets sold is 271
<em><u>Solution:</u></em>
Let "p" be the number of presale tickets sold
Let "g" be the number of tickets sold at gate
<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>
Therefore,
Presale tickets + tickets sold at gate = 800
p + g = 800 ------ eqn 1
<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>
Therefore,
Number of tickets sold at gate = twice the number of pre-sale tickets - 13
g = 2p - 13 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 2 in eqn 1
p + 2p - 13 = 800
3p -13 = 800
3p = 800 + 13
3p = 813
p = 271
Thus 271 presale tickets were sold
Answer:
"Let the smaller value a = <u>10</u> and the larger value b = <u>100</u>. Than a^2 + 2ab + b^2 is <u>10^2 + 2 * 10 * 100 + 100^2</u>. This can be simplified to <u>12100</u>. So, 110^2 is equal to <u>12100</u>."
Hope this helped!
Answer:
A
Step-by-step explanation:
gimme brainliest
Step-by-step explanation:
G(x) = 2/3 x - 6 switch x and y around and solve for y.
y = 2/3 x - 6
x = 2/3 y - 6
x + 6 = 2/3 y
3/2 x + 9 = y
Answer:
0.3 is the answer
Step-by-step explanation:
