<h3>I'll teach you how to solve h-(-2.22)=-7.851</h3>
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h-(-2.22)=-7.851
Apply rule:
h+ -2.22=-7.851
Subtract 2.22 from both sides:
h+ -2.22-2.22 =-7.851-2.22
Simplify:
h= -10.071
Your Answer Is h= -10.071
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Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Terms/Coefficients
- Functions
- Function Notation
- Graphing
- Solving systems of equations
<u>Calculus</u>
Area - Integrals
Integration Rule [Reverse Power Rule]: 
Integration Rule [Fundamental Theorem of Calculus 1]: 
Integration Property [Addition/Subtraction]: ![\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cint%20%7B%5Bf%28x%29%20%5Cpm%20g%28x%29%5D%7D%20%5C%2C%20dx%20%3D%20%5Cint%20%7Bf%28x%29%7D%20%5C%2C%20dx%20%5Cpm%20%5Cint%20%7Bg%28x%29%7D%20%5C%2C%20dx)
Area of a Region Formula: ![\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A%20%3D%20%5Cint%5Climits%5Eb_a%20%7B%5Bf%28x%29%20-%20g%28x%29%5D%7D%20%5C%2C%20dx)
Step-by-step explanation:
*Note:
<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>
<u />
<u>Step 1: Define</u>
f(x) = x²
g(x) = x⁶
Bounded (Partitioned) by x-axis
<u>Step 2: Identify Bounds of Integration</u>
<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>
Simply graph the functions to see where the functions intersect (See Graph Attachment).
Interval: [-1, 1]
Lower bound: -1
Upper Bound: 1
<u>Step 3: Find Area of Region</u>
<em>Integration</em>
- Substitute in variables [Area of a Region Formula]:
![\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A%20%3D%20%5Cint%5Climits%5E1_%7B-1%7D%20%7B%5Bx%5E2%20-%20x%5E6%5D%7D%20%5C%2C%20dx)
- [Area] Rewrite [Integration Property - Subtraction]:

- [Area] Integrate [Integration Rule - Reverse Power Rule]:

- [Area] Evaluate [Integration Rule - FTC 1]:

- [Area] Subtract:

Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Area Under the Curve - Area of a Region (Integration)
Book: College Calculus 10e
14. For a prism, the volume is given by
.. V = Bh . . . . . . . . where B is the area of the base, and h is the height of the prism
For a pyramid, the volume is given by
.. V = (1/3)*Bh . . . . where B is the area of the base, and h is the height of the pyramid
The volume is proportional to the area of the base. If the dimensions of the base decrease linearly to zero at the height of the geometry as they do for pyramids and cones, then the volume formula includes a factor of 1/3.
15b. The volume of a pyramid is 1/3 that of a prism with the same base area and height.
Sorry I cant help you with that good luck with that.