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2 years ago

8

Joaquin wants to make his famous chocolate chip cookies to bring to his friend's birthday party. The original recipe serves 8 pe

ople and requires one half of a cup of butter, but he needs it to serve 28 people. How many cups of butter will he need?

1 answer:

Alexandra [31]2 years ago

6 0

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I NEED HELP RIGHT NOW PLEASE!!!!!!!!!!<br> h-(-2.22)=-7.851

Leviafan [203]

<h3>I'll teach you how to solve h-(-2.22)=-7.851</h3>

---------------------------------------------------------

h-(-2.22)=-7.851

Apply rule:

h+ -2.22=-7.851

Subtract 2.22 from both sides:

h+ -2.22-2.22 =-7.851-2.22

Simplify:

h= -10.071

Your Answer Is h= -10.071

plz mark me as brainliest :)

6 0

4 years ago

Ally rolls an octahedron-shaped (8-sided) die with the number 1, 2, 3, 4, 5, 6, 7, or 8 on each face. What is the probability of

kirza4 [7]

Answer:

25%

Step-by-step explanation:

6 0

2 years ago

Find the area of the region enclosed by the graphs of the functions

Vaselesa [24]

Answer:

$\displaystyle A = \frac{8}{21}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

Terms/Coefficients
Functions
Function Notation
Graphing
Solving systems of equations

<u>Calculus</u>

Area - Integrals

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

Area of a Region Formula: $\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx$

Step-by-step explanation:

*Note:

<em>Remember that for the Area of a Region, it is top function minus bottom function.</em>

<u />

<u>Step 1: Define</u>

f(x) = x²

g(x) = x⁶

Bounded (Partitioned) by x-axis

<u>Step 2: Identify Bounds of Integration</u>

<em>Find where the functions intersect (x-values) to determine the bounds of integration.</em>

Simply graph the functions to see where the functions intersect (See Graph Attachment).

Interval: [-1, 1]

Lower bound: -1

Upper Bound: 1

<u>Step 3: Find Area of Region</u>

<em>Integration</em>

Substitute in variables [Area of a Region Formula]: $\displaystyle A = \int\limits^1_{-1} {[x^2 - x^6]} \, dx$
[Area] Rewrite [Integration Property - Subtraction]: $\displaystyle A = \int\limits^1_{-1} {x^2} \, dx - \int\limits^1_{-1} {x^6} \, dx$
[Area] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle A = \frac{x^3}{3} \bigg| \limit^1_{-1} - \frac{x^7}{7} \bigg| \limit^1_{-1}$
[Area] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = \frac{2}{3} - \frac{2}{7}$
[Area] Subtract: $\displaystyle A = \frac{8}{21}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Area Under the Curve - Area of a Region (Integration)

Book: College Calculus 10e

6 0

3 years ago

I have 15a but I need 15b and 14

Naily [24]

14. For a prism, the volume is given by
.. V = Bh . . . . . . . . where B is the area of the base, and h is the height of the prism

For a pyramid, the volume is given by
.. V = (1/3)*Bh . . . . where B is the area of the base, and h is the height of the pyramid

The volume is proportional to the area of the base. If the dimensions of the base decrease linearly to zero at the height of the geometry as they do for pyramids and cones, then the volume formula includes a factor of 1/3.

15b. The volume of a pyramid is 1/3 that of a prism with the same base area and height.

8 0

3 years ago

Hi can someone help with this question? Thanks!!!

aleksandrvk [35]

Sorry I cant help you with that good luck with that.

4 0

3 years ago