Answer:
7A−(I + A)³
=7A−(1³ + A³ +3.I.A² +3.1².A)
=7A−(I+ A².A+3A² +34)
= 7A-(I+A.A+3A+34) (*: A² = A)
=7A-(I+ A² +6A)
= 7A-(I+A+64)
=7A-(1+7A)
=7A-I-7A
=-1
The vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be:
B. x = 0
C. x = +-2π
<h3>How to illustrate the information?</h3>
It should be noted that the function that's given from the information illustrated is given as:
y = 3 for (x/2) - 4
It should be noted that there is no phase shift and the period is 2π.
It should be noted that the vertical asymptote will be x = 3πn where no is represented as the integer at n = 0, 1, and -1.
Therefore, the vertical asymptote of the function that are illustrated in the calculus and the function y = 3cot(1/2x) - 4 will be x = 0 and x = +2π.
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Answer:
435
Step-by-step explanation:
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30*0.0= 435
Answer:
195 cubic centimeters (cm^3)
Step-by-step explanation:
sorry it's late