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ELEN [110]
3 years ago
8

Name one possible cross section of a sphere

Mathematics
2 answers:
Lisa [10]3 years ago
8 0
A "cross section" is basically the two-dimensional face that you get when you cut a three-dimensional figure a certain way.  For example, imagine you're buttering your bread.  When you cut a pat of butter off, what shape is left on the butter?  A square!

So, imagine cutting a ball in half.  What shape is left?  A circle!

Answer: circle
VLD [36.1K]3 years ago
8 0
The answer would be a circle.imagine a watermelon right,cutting it in half, you would see a circle that forms inside of the watermelon
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How many solutions does 4(x-5)+2=4x—18 have??
baherus [9]
Only one. These problems always have one solution unless something has changed.
4 0
4 years ago
What are the real solutions of x squared =225
Gnesinka [82]

The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.

<h3>What are the real solutions of the equation as given in the task content?</h3>

It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;

x² = 225

x = ± 15

Therefore, the real solutions of the equation are; +25 and -25.

Read more on real solutions of equations;

brainly.com/question/3122484

#SPJ1

3 0
2 years ago
Find the value of the following expression:
Greeley [361]

Answer:

25

Step-by-step explanation:

Expression: <em>(2⁸ ⋅ 5⁻⁵ ⋅ 19⁰)⁻² ⋅ (5⁻²/2³)⁴ ⋅ 2²⁸</em>

Inner-most powers: 2⁻¹⁶ • 5¹⁰ • 1 • 5⁻⁸/2¹² • 2²⁸

Combine like terms: 2¹² • 5²/2¹²

Cancel out: 5²

Solve: 25

6 0
4 years ago
The endpoints of the diameter of a circle are (−2, −3) and (4, −1). Which equation represents the circle?
Alika [10]

Answer:

The equation of circle is (x-1)^{2}+(y-2)^{2} = 18

Step-by-step explanation:

Given the endpoints of the diameter of a circle: (-2,-3) and (4,-1)

We know that the equation of circle is

(x-h)^{2} + (y-k)^{2}= r^{2}

where (x,y) is any point on the circle, (h,k) is center of the circle and r is radius of circle.

To find (h,k): the center is midpoint of diameter

Midpoint of diameter with end points (x1,y1) and (x2,y2) is given by

(  \frac{x1+x2}{2} , \frac{y1+y2}{2}  )

( \frac{-2+4}{2} , \frac{-3-1}{2}  )

(1,2)

Hence (h,k) is (1,2)

Substituting values of (h.k) and (x.y) as (1,2) and (4,-1) respectively in equation of circle, we get

(4-1)^{2} +(-1-2)^{2} = r^{2}

r^{2} = 18

Now substituting values of (h,k) and r^{2} in equation of circle, we get

(x-1)^{2}+(y-2)^{2} = 18

Hence the equation of circle is (x-1)^{2}+(y-2)^{2} = 18

5 0
3 years ago
Read 2 more answers
The weight of an object on the moon varies directly as its weight on Earth. With all of his gear on, Neil Armstrong weighed 360
babymother [125]

amistre64 Medals 0
e = k.m
360 = k.60
k = 360/60 = 36/6 = 6
108 = 6.m
108/6 = m = 18 
8 0
4 years ago
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