Name one possible cross section of a sphere
2 answers:
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<u>Answer: </u>
The point-slope form of the line that passes through (6,1) and is parallel to a line with a slope of -3 is 3x + y – 19 = 0
<u>Solution: </u>
The point slope form of the line that passes through the points and parallel to the line with slope “m” is given as
--- eqn 1
Where “m” is the slope of the line. are the points that passes through the line.
From question, given that slope “m” = -3
Given that the line passes through the points (6,1).Hence we get
By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -3 can be found out.
y – 1 = -3(x – 6)
y – 1 = -3x +18
On rearranging the terms, we get
3x + y -1 – 18 = 0
3x + y – 19 = 0
Hence the point slope form of given line is 3x + y – 19 = 0