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4 years ago

Solve for y 2y + 6 = 1 - 3y

Mathematics

2 answers:

UNO [17]4 years ago

6 0

Answer:

-1

Step-by-step explanation:

2y+6=1 -3y

add three to both sides and minus 6 from both sides becasue you want to get y by itself

5y=-5

now both sides by 5

y=-1

belka [17]4 years ago

5 0

Answer:

y=−1

Step-by-step explanation:

2y+6=1−3y

Step 1: Simplify both sides of the equation.

2y+6=1−3y

2y+6=1+−3y

2y+6=−3y+1

Step 2: Add 3y to both sides.

2y+6+3y=−3y+1+3y

5y+6=1

Step 3: Subtract 6 from both sides.

5y+6−6=1−6

5y=−5

Step 4: Divide both sides by 5.

y=−1

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3y – 6x = 3 y = 2x + 1

Keith_Richards [23]

Answer:

infinite solutions along the line y = 2x+1

Step-by-step explanation:

3y – 6x = 3

y = 2x + 1

Replace y in the first equation with the second equation

3 ( 2x+1) -6x =3

6x +3 -6x = 3

3=3

This is always true so there are infinite solutions along the line y = 2x+1

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3 years ago

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Pavel [41]

Answer: non ya

Step-by-step explanation:

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3 years ago

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lesya692 [45]

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1 year ago

Which of the following functions represent exponential decay?

Zina [86]

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ is the function that represent exponential decay.

Explanation:

The exponential decay can be represented by

$f(x)=a \cdot b^{x}$ where $a>0$ and $0$

Option A: $f(x)=3(1.7)^{x-2}$

From the function, we can see that $a=3$ and $b=1.7$

Thus, $a>0$ and $b>1$

Thus, the function $f(x)=3(1.7)^{x-2}$ does not represent exponential decay.

Hence, Option A is not the correct answer.

Option B: $f(x)=3(1.7)^{-2 x}$

From the function, we can see that $a=3$ and $b=1.7$

Thus, $a>0$ and $b>1$

Thus, the function $f(x)=3(1.7)^{-2 x}$ does not represent exponential decay.

Hence, Option B is not the correct answer.

Option C: $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$

From the function, we can see that $a=3^5=243$ and $b=\frac{1}{3} =0.3333$

Thus, $a>0$ and $0$

Thus, the function $f(x)=3^{5}\left(\frac{1}{3}\right)^{x}$ represent exponential decay.

Hence, Option C is the correct answer.

Option D: $f(x)=3^{5}(2)^{-x}$

From the function, we can see that $a=3^5=243$ and $b=2$

Thus, $a>0$ and $b>1$

Thus, the function $f(x)=3^{5}(2)^{-x}$ does not represent exponential decay.

Hence, Option D is not the correct answer.

8 0

4 years ago

The leg of a right triangle are 3 units and 10 units. What is the length of the hypotenuse? Round your answer to the nearest hun

Andreas93 [3]

Hey there! This is gonna require the Pythagorean Theorem which is<span> a^2 + b^2 = c^2
</span>
a and b in this case are the legs while c is the hypotenuse! So, we can just plug in the numbers we know!

3^2 + 10^2 = c^2

9 + 100 = c^2

109 = c^2

And then take the square root of 109 to get the hypotenuse.

<span>10.4403065089 = c
</span>
Since we need to round to the nearest hundredth, though, it would be 10.44

I hope that helps! Feel free to let me know if you have any questions!

- mathwizzard3

6 0

3 years ago