The standard form is
(x-xo)² + (y-yo)² = r²
Where xo,yo is the center of the circumference
and r is the radius.
We find the distance between the points to determine the <span>diameter
d=sqrt ((9-2)</span>² + (4-4)²<span>) = sqrt (49) = 7
The radius of the circumference is d/2 = 7/2 = 3.5
And we can see that those points are at the same coordinate y = 4
The center is given then by , x = (9+2)/2 = 5.5
y = (4+4)/2 = 4
The equation results
(x-5.5)</span>² + (y-4)² = (3.5)²<span>
</span>
Answer:
step by step
Step-by-step explanation:
where
r = radius
h= height
Area of a cylinder = 2πrh+2πr^2
Area of a cylinder = 2π8(3)+2π8^2
Area of a cylinder = 176π = 552.92
Area of a hemisphere= 3r2π
Area of a hemisphere= 3(2)2π
Area of a hemisphere= 12π = 37.699111843
Area of the cylinder in this problem
176π - 12π = 164π
Answer:
Rectangular area as a function of x : A(x) = 200*x + 2*x²
A(max) = 5000 m²
Dimensions:
x = 50 m
l = 100 m
Step-by-step explanation:
"x" is the length of the perpendicular side to the wall of the rectangular area to be fenced, and we call "l" the other side (parallel to the wall of the barn) then:
A(r) = x* l and the perimeter of the rectangular shape is
P = 2*x + 2*l but we won´t use any fencing material along the wll of the barn therefore
P = 2*x + l ⇒ 200 = 2*x + l ⇒ l = 200 - 2*x (1)
And the rectangular area as a function of x is:
A(x) = x * ( 200 - 2*x) ⇒ A(x) = 200*x + 2*x²
Taking derivatives on both sides of the equation we get:
A´(x) = 200 - 4*x ⇒ A´= 0
Then 200 - 4*x = 0 ⇒ 4*x = 200 ⇒ x = 50 m
We find the l value, plugging the value of x in equation (1)
l = 200 - 2*x ⇒ l = 200 - 2*50 ⇒ l = 100 m
A(max) = 100*50
A(max) = 5000 m²
Answer:scales percent error=3.51%
Step-by-step explanation:
P ercent error = Experimental value - Theoretical value /Theoretical value x 100
Theoretical value = 6255 grams
Experimental value ( use of scale ) = 6475grams
Percent error =(6475- 6255)grams / 6255grams x 100
=220/6255 x 100
=3.51%
