how many ounces of water must be added 100 oz. of 60% iodine to produce a 55% solution ? round your answer to the nearest hundre

Question

2 years ago

11

th.

2 answers:

algol [13] · Answer 1 · 2023-06-16T15:21:14+03:00

algol [13]2 years ago

8 0

Answer:

10 ounces

Step-by-step explanation:

miv72 [106K] · Answer 2 · 2023-06-16T16:37:32+03:00

Answer:

9.09 ounces

Step-by-step explanation:

The added water can be calculated by writing an equation for the amount of iodine in the diluted solution.

<h3>Setup</h3>

Let x represent the number of ounces of water added to the 60% solution. The total amount of iodine in the mixture is ...

0.60(100) +0(x) = 0.55(100+x) . . . . . ounces of iodine in the mix

<h3>Solution</h3>

Simplify the equation:

60 = 55 +0.55x

5 = 0.55x . . . . . . . subtract 55

x = 5/0.55 ≈ 9.09

9.09 ounces of pure water must be added to produce a 55% solution.