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Klio2033 [76]
2 years ago
5

What is the pH of a 1.0 x 10-5 M solution of sulfric acid

Chemistry
1 answer:
Anika [276]2 years ago
5 0

Answer:

pH = 4.7

Explanation:

The pH is a measurement of acidity using the concentration of hydrogen ions (H⁺) in a solution. Therefore, before you can find the pH, you need to determine the concentration (M) of H⁺ in the solution. This can be done by multiplying the molarity of the solution by the amount of H⁺ in the solution.

1 mole H₂SO₄ = 2 moles H⁺ and 1 mole SO₄⁻

1.0 x 10⁻⁵ M H₂SO₄           2 moles H⁺
-----------------------------  x  ----------------------  =  2.0 x 10⁻⁵ M H⁺
                                        1 mole H₂SO₄

To find the pH, you need to use the following equation:

pH = -log[H⁺]

Since you calculated the hydrogen concentration ([H⁺]) in the previous step, you can plug it into the equation and solve.

pH = -log[H⁺]

pH = -log[2.0 x 10⁻⁵]

pH = 4.7

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Your teacher needs a 3.0M solution acid, but only has a 12.0M stock solution of sulfuric acid in the chemical store room. Calcul
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Answer:

The calculations are in the explanation below.

The <em>steps </em>are:

  • 1. Using a graduated pipette, accurately take 25mL of the 12.0M stock solution.
  • 2. Pour the 25mL of stock solution into a 100 mL volumetric flask
  • 3. Add distilled water up to the mark
  • 4. Cap the flask with the stopper
  • 5. Stirr by gently rotating the flask.

Explanation:

To make 100 mililiter of the 3.0M solution of sulfuric acid, first you must calculate the volume of the 12.0M stock solution that contains the same number of moles as the diluted solution.

For that, you use the dilution formula:

  • number of moles = C₁V₁ = C₂V2
  • 12.0M×V₁ = 3.0M × 100mL
  • V₁ = 3.0M × 100mL/12.0M = 25mL

Then, the steps are:

1. Using a graduated pipette, accurately take 25mL of the 12.0M stock solution.

2. Pour the 25mL of stock solution into a 100 mL volumetric flask

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