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maw [93]
3 years ago
15

What is the balanced equation of K3PO4 + HCI -> KCI + H3PO4?

Chemistry
1 answer:
laiz [17]3 years ago
5 0

Answer:

K₃PO₄ + 3HCl ⇒ 3KCl + H₃PO₄

Explanation:

practice these, it gets easier. goal is to match the amount of reactants and products on both sides of the equation. cheers!

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If the same large amount of heat is added to a 250 g piece of aluminum and a 150 g piece of aluminum, what will happen? The 150
Inga [223]

Answer:

The 150 g Al will reach a higher temperature.

Explanation:

  • The amount of heat added to a substance (Q) can be calculated from the relation:

<em>Q = m.c.ΔT.</em>

where, Q is the amount of heat added,

m is the mass of the substance,

c is the specific heat of the substance,

ΔT is the temperature difference (final T - initial T).

Since, Q and c is constant, ΔT will depend only on the mass of the substance (m).

∵ ΔT is inversely proportional to the mass of the substance.

<em>∴ The piece with the lowest mass (150.0 g) will reach a higher temperature than that of a higher mass (250.0 g).</em>

<em>So, the right choice is: The 150 g Al will reach a higher temperature.</em>

3 0
3 years ago
When blending substances and you do so unevenly, you can describe
zavuch27 [327]
B.) Heterogeneous
The prefix homo is referred to meaning the same or equal
8 0
3 years ago
Types of catalyst..... <br>Plsz..... ​
Fantom [35]

Answer:



Explanation:

(1) Homogeneous, (2) Heterogeneous (solid), (3) Heterogenized homogeneous catalyst and (4) Biocatalysts

4 0
3 years ago
Which statement explains how ATP and it's phosphate groups are relatedto energy that is used in plant processes
Zolol [24]

Hi my dear friend,

The statement that explain how ATP and its phosphate groups are related to energy used in plant process is that ADP gains a phosphate to create ATP, which stores energy for making sugars. These packets of energy in the form of ATP are then broken down to release energy and use that energy in synthesis of glucose.

~Thank you

8 0
4 years ago
A sample may contain any or all of the following ions: Hg22+, Ba2+, Mn2+. No precipitate formed when an aqueous solution of NaCl
Bess [88]

Answer:

Only Mn⁺² is present.

Explanation:

  • When an aqueous solution of NaCl is added, the Cl⁻ species is introduced. In the presence of Cl⁻, Hg₂²⁺ would precipitate as Hg₂Cl₂.
  • When an aqueous solution of Na₂SO₄ is added, the SO₄⁻² species is introduced. In the presence of SO₄⁻², Ba⁺² would precipitate as BaSO₄.

No precipitate formed when either of these solutions were added, thus <u>the sample does not contain Hg₂⁺² nor Ba⁺²</u>.

  • Under basic conditions Mn⁺² would precipitate as Mn(OH)₂. A precipitate formed once the solution was made basic, so <u>the sample contains Mn⁺²</u>.
3 0
3 years ago
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