Answer:
2 grams.
Explanation:
H2 + O2 ---> H2O2
Using molar masses:
2*1 g hydrogen reacts with 2*16 g oxygen.
so 2g H2 reacts with 32 g O2.
Li+ has a smaller ionic radius than K+
and smaller molecules have more collisions/interactions between each other
<h3>What is ion-solvent interaction ?</h3>
In the case of ion-solvent interactions, the state in which the interac-tions exist is an obvious one; it is the situation in which ions are inside the solvent.
- Ions are charged particles, and charges interact with other charges. So there will also be ion-ion, as well as ion-solvent, interactions in the solution.
- In the process of solvation, ions are surrounded by a concentric shell of solvent. Solvation is the process of reorganizing solvent and solute molecules into solvation complexes.
Learn more about Ion-solvent interaction here:
brainly.com/question/21307101
#SPJ4
Explanation:
1. Elements are substances made of the same kind of atoms, unlike compounds that are combination for different kinds of atoms. The elements in the reaction therefore are;
Cl and O₃
2. Yes, the equation is balanced. There is the same number of each element on either side of the equation. One (1) CL and three (3) O atoms.
3. Ozone is reduced. Other the other hand, Cl is oxidized. Remember a reduction reaction may involve the loss of one or more oxygen atoms or the acceptance of electrons. This occurs for O₃ which is reduced to O₂.
4. The equation complies with the conservation of matter as in the first law of thermodynamics. The number of atoms for each element on the other side of the equation remains the same. This means no matter(which also translated to energy) has been created or destroyed in the process.
Answer:
Percent composition tells you which types of atoms (elements) are present in a molecule and their levels. Percent composition can also tell you about the different elements present in an ionic compound as well.
☀️
Molar mass of 


<u>As we know</u>–
1 mol =
formula units
1 mol
= 143.092 g =
formula units
Henceforth –
formula units
–


