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Maksim231197 [3]
3 years ago
9

A.Which non-metal is essential for our life and all living beings inhale it during breathing?

Chemistry
2 answers:
vodomira [7]3 years ago
6 0

Answer:

A. oxygen

B. chlorine

2. iodine

(a) because aluminium is a soft malleable metal. it can be made to in sheets to form thin wrapping sheets. also, it does not react with food items.

(b) because metals are good conductors of heat and electricity. the immersion rod needs electric supply to get heated and to heat liquids.

(c)  they're kept in kerosene to keep them from coming in contact with oxygen and moisture as they react to form their hydroxides.

4. Magnesium is a metal. Metals react with oxygen to form metallic oxides. So Magnesium oxides are basic in nature. But nonmetals react with oxygen to form nonmetallic oxides. These oxides differ from metallic oxides because they are acidic in nature. Nonmetallic oxides react with water to form acids. Therefore, Sulphur dioxide is acidic in nature. Magnesium oxide is basic in nature.

5. Copper forms a green deposit on its surface when exposed to air which is usually a mixture of copper carbonate and copper hydroxide. It's acidic in nature.

Mandarinka [93]3 years ago
5 0

Answer:

2.A

Explanation:

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The pressure exerted by an individual gas in a mixture is known as its partial pressure and assuming we have a mixture of ideal gases and we can use the ideal gas law to solve problems involving gases in a mixture and the ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components

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a) One kmol of N2O4 dissociates at 25℃, 1 atm to form an equilibrium ideal gas mixture of N2O4 and NO2 in which the amount of N2
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Answer:

neq N2O4 = 0.9795 mol.....P = 0.5 atm; T = 25°C

Explanation:

             ni      change    eq.

N2O4    1          1 - x       0.8154.....P = 1 atm; T = 25°C

NO2      0        0 + x          x

∴ x = neq = Peq.V / R.T.....ideal gas mix

if P = 0.5 atm, T = 25°C; assuming: V = 1 L

⇒ x = neq = ((0.5 atm)(1 L))/((0.082 atm.L/K.mol)(298 K))

⇒ x = neq = 0.0205 mol

⇒ neq N2O4 = 1 - x = 1 - 0.0205 = 0.9795 mol

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