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Kisachek [45]
2 years ago
13

A company that produces dog food claims that its bags contain 11 kg of food. From

Mathematics
1 answer:
andriy [413]2 years ago
3 0

By testing the hypothesis we can conclude that the bag does not contain 11 kg of food.

Given mean of 10.6 kg, population standard deviation of 0.6 and sample size of 25.

We are required to find whether the company is right in saying that their bags contain 11 kg of food.

First we have to make hypothesis.

H_{0}:μ≠11

H_{1}:μ=11

We have to use t statistic because the sample size is less than 30.

t=(X-μ)/s/\sqrt{n}

We will use s/\sqrt{n}=0.6 because we have already given population standard deviation of weights.

t=(11-10.6)/0.6

=0.4/0.6

=0.667

Degree of freedom=n-1

=25-1

=24

T critical at 0.05 with degree of freedom 24=2.0639

T critical at 0.05 with degree of freedom is greater than calculated t so we will accept the null hypothesis.It concludes that the bags donot contain 11 kg of food.

Hence by testing the hypothesis we can conclude that the bag does not contain 11 kg of food.

Learn more about t test at brainly.com/question/6589776

#SPJ1

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32km

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Integrate t sec^2 (2t) dt
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F = t ⇨ df = dt 
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⇔ 
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt 
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As integral of tan u = - ln (cos (u)), you get : 

integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant 
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David has an after-school job at an animal shelter he notices that at one meal for dogs can eat three cans of food
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what are you asking?

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A software designer is mapping the streets for a new racing game. all of the streets are depicted as either perpendicular or par
ElenaW [278]

The equation of the central street PQ is  -1.5x - 3.5y = -31.5 option (b) is correct.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

We have a straight line:

-7x+3y=-21.5  

Convert it to the general form given below:

\rm y=mx+c

\rm 3y=-21.5+7x\\\\ \rm y = \frac{-21.5}{3}+\frac{7}{3}x or

\rm y = \frac{7}{3}x-\frac{21.5}{3}

m = \frac{7}{3}   (Slope of AB line)

For the slope(m') of the PQ line:

\rm m'=-\frac{1}{m}    ( because AB and PQ are perpendicular to each other)

\rm m' = -\frac{3}{7}

We know the:

\rm (y-y')=m'(x-x')

Where (x', y') = (7, 6), we get:

\rm (y-6)=-\frac{3}{7} (x-7)

\rm 7(y-6)=-3 (x-7)\\\\\rm 7y-42= -3x+21\\\\\rm 7y= -3x+21+42\\\\\rm 3x+7y=63

\rm -1.5x-3.5y=-31.5   (multiply by -1/2 on both sides)

Thus, the equation of the central street PQ is  -1.5x - 3.5y = -31.5

Learn more about the straight line.

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