Answer:
Step-by-step explanation:
c
 
        
             
        
        
        
Answer:
No, doubling the base and height would actually quadruple the area,
Step-by-step explanation:
With the original measurements of b = 3 ft and h = 5 ft, 
<em>b x h = A</em>
<em>(3) x (5) = </em><em>15 ft</em>
So lets say we <em>doubled</em> the factors:
<em>(2)(3) x (2)(5) = A</em>
We would end up with 60 feet, four times that of 15.
<em>(6) x (10) = </em><em>60 ft</em>
 
        
             
        
        
        
Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
 
        
             
        
        
        
[ Answer ]

[ Explanation ]
- Factor:  (a - 3) + q(a - 3) (a - 3) + q(a - 3)
-------------------------------------
- Expand  : : 

 :
: 

![\boxed{\bold{[] \ Eclipsed \ []}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cbold%7B%5B%5D%20%5C%20Eclipsed%20%5C%20%5B%5D%7D%7D)
 
        
             
        
        
        
Answer:

Step-by-step explanation:
1) Use square sum: (a + b)² = a² + 2ab + b².

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u>²</u><u> </u><u>+</u><u> </u><u>2xy</u><u> </u><u>+</u><u> </u><u>y</u><u>²</u>.