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Len [333]
2 years ago
10

If you need help- an anything just and MATH OR SIENT

Mathematics
1 answer:
galben [10]2 years ago
3 0
It won’t let me add:(
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Solve this question ​
love history [14]

Answer:

\frac{4x - 11}{2}  \leqslant 3x - 3 < 4 \\  \\   =  > \frac{4x - 11}{2}  \leqslant 3x - 3 \: and \: 3x - 3 < 4 \\  \\  <  =  > 4x - 11 \leqslant 6x - 6 \:  \: and \:  \: 3x < 7 \\  \\  <  =  > 2x \geqslant  - 5 \:  \: and \:  \: x <  \frac{7}{3}  \\  \\  <  =  >  \frac{ - 5}{2}  \leqslant x <  \frac{7}{3}

=> the greatest integer is 2

the smallest integer is -2

3 0
3 years ago
What is the quotient of 5,256 ÷ 52?
denis23 [38]

Answer:

5,256 - 4 = 5,252 = 52 x 101 or 101.0769230769231

Step-by-step explanation:

3 0
3 years ago
Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0
2 years ago
Which one is correct
Alexandra [31]

Answer:

i believe its false good Sir

6 0
2 years ago
Read 2 more answers
Where is the hole for the following function located?
Drupady [299]

<em>At x = -3 is located a hole. </em>

<h2>Explanation:</h2>

In this problem, we have the following function:

f(x)=\frac{x+3}{(x-4)(x+3)}

A hole will lie at the x-values that makes the function undefined, that is, when the denominator is zero. In a mathematical language:

(x-4)(x+3)=0

From this equation, we get two solutions:

x=4 \\ \\ x=-3

At those x-values the function will have a hole. From the choices:

<em>At x = -3 is located a hole. </em>

<h2>Learn more:</h2>

Derivative: brainly.com/question/13419010

#LearnWithBrainbly

7 0
2 years ago
Read 2 more answers
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