Using the diagonal dimension and the height we can solve for the diameter of the cylinder using the Pythagorean theorem.
x^2 + 9.5^2 = 19.3^2
x^2 + 90.25 = 372.49
x^2 = 372.49 - 90.25
x^2 = 282.24
x = √282.24
x = 16.8
Now we know the diamteer and height, we can calculate the volume using the formula V = pi * r^2 * h
r = 1/2 the diameter = 16.8/2 = 8.4
using 3.14 for pi
Volume = 3.14 * 8.4^2 * 9.5
V = 3.14 * 70.56 * 9.5
v = 3.14 * 670.32
v = 2104.8 cubic meters
now, you're asked to use it when ln(1.38), which is just another way of saying x = 1.38
so set x = 1.38 and see what "y" is
Answer:
y = -2x + 5
Step-by-step explanation:
y=
-3
Slope of this line m₁ = 1/2
Slope of the line perpendicular to this line = m₂
m₁ *m₂ = -1
m₂ = -1 *2/1 = -2
Slope = -2; (1,3)
y- y₁ = m(x-x₁)
y - 3 = -2(x - 1)
y - 3 = -2x + 2
y = -2x +2 +3
y = -2x + 5
9514 1404 393
Explanation:
Here's one way to go at it.
Draw segments AB and CO. Define angles as follows. (The triangles with sides that are radii are all isosceles, so their base angles are congruent.)
x = angle OAB = angle OBA
y = angle OAC = angle OCA
z = angle OBC = angle OCB
Consider the angles at each of the points A, B, C.
At A, we have ...
angle CAB = x + y
At B, we have ...
angle CBA = x + z
At C, we have ...
angle ACB = y + z
The sum of the angles of triangle ABC is 180°, as is the sum of angles in triangle ABO. This gives ...
x + x + ∠AOB = (x+y) +(x+z) +(y+z)
∠AOB = 2(y+z) = 2∠ACB
This shows ∠AOB = 2×∠C, as required.
