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Ne4ueva [31]
3 years ago
8

Marco is carrying two cylinder-shaped cans. Each can has the same height

Mathematics
2 answers:
Dafna11 [192]3 years ago
8 0

Answer:

Choice D

Step-by-step explanation:

The Cavalieri's principle states that if two or more solids have identical cross-sectional area as well as height, then the solids will have equal volume.

Therefore, the volumes of the cylinders are the same

Hunter-Best [27]3 years ago
4 0

Answer:

The volumes of the cylinders are the same.

Step-by-step explanation:

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P= ? , r=4%, t=3 months, I=$20
Scilla [17]
<span>Answer:

P = $ 2,000.00

Equation:
P = I / rt
Calculation:
First, converting R percent to r a decimal
r = R/100 = 4%/100 = 0.04 per year,
putting time into years for simplicity,
3 months ÷ 12 months/year = 0.25 years,
then, solving our equation

P = 20 / ( 0.04 × 0.25 ) = 2000
P = $ 2,000.00

The principal required to
accumulate interest of $ 20.00
on a rate of 4% per year for 0.25 years (3 months) is $ 2,000.00.
</span>
3 0
3 years ago
What is the measure of x? Help me on this Geometry question.​
AlladinOne [14]

Answer:

21°

Step-by-step explanation:

the angles of triangle abc has to = 180 so subtract the known angles to get 21

angles bca and daf have to be the same so its 21

8 0
4 years ago
Read 2 more answers
Can you answer this please ?
chubhunter [2.5K]

Answer: 91


Step-by-step explanation:


4 0
3 years ago
Assuming that the population is normally​ distributed, construct a 9090​% confidence interval for the population mean for each o
jasenka [17]

Given:

Set A: 1 4 4 4 5 5 5 8

Mean: 4.5

Standard dev: 1.9

 

Set B:

Mean: 4.5

Standard dev: 2.45

 

% =  90 

Set A:

Standard Error, SE = s/ √n =    1.9/√8 = 0.67  

Degrees of freedom = n - 1 =   8 -1 =  7   

t- score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.67 = 1.272685913

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.272685913 = 3.23

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.272685913 = 5.77

The 90% confidence interval is [3.23, 5.77]

 

Set B:

Standard Error, SE = s/ √n =    2.45/√8 = 0.87  

Degrees of freedom = n - 1 =   8 -1 = 7   

t- Score =  1.89457861

<span> <span><span> <span>   </span> </span> </span></span>

Width of the confidence interval = t * SE =     1.89457861* 0.87 = 1.641094994

Lower Limit of the confidence interval = x-bar - width =      4.5 - 1.641094994 = 2.86

Upper Limit of the confidence interval = x-bar + width =      4.5 + 1.641094994 = 6.14

The 90% confidence interval is [2.86, 6.14]

 

<span>We can obviously see that sample B has more variation in the scores than sample A. The fact that the standard deviation is 2.45 for B and 1.9 for A). Therefore, they yield dissimilar confidence intervals even though they have the same mean and range.</span>

6 0
3 years ago
Find the sum of each set of numbers, as well as the size n of each set of numbers (n = number of numbers in the set). Use these
guapka [62]

We have to add numbers without a calculator.

1) 25, 35, 19, 31

We can group them by the last digit, so they are easy to add:

25 + 35 = 20 + 30 + 5 +5 = 50 + 10 = 60

19 + 31 = 10 + 30 + 9 +1 = 40 + 10 = 50

Then, 60 + 50 = 110

numbers in the set n = 4

Sum = 110

2) 101, 73, 49, 27, 24, 36

We can group them again by the last digit (adding 10, like the previous example).

We can substract the last digit from one number and add it to the other one. The result will be the same, but they will become easier to add.

101 + 49 = 100+50 = 150

73 + 27 = 70 + 30 = 100

24 + 36 = 20 + 40 = 60

150 + 100 + 60 = 250 + 60 = 310

numbers in the set n = 6

Sum = 310

3) 25, 25, 25, 30, 30, 30, 32, 32, 32

In this case we have 3 times the same numbers, so we can add the three different numbers and then multiply the total by 3.

We can use the properties of the multiplication to simplify the product (we will use the distributive property)

25 + 30 + 32 = 27 + 30 + 30 = 87

87 * 3 = 80*3 + 7*3 = 240 + 21 = 261

numbers in the set n = 9

Sum = 261

8 0
1 year ago
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