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OleMash [197]
1 year ago
10

Dema's truck gets 32 mpg on the highway and 18 mpg in the city. The amount of gas he uses A (in gal) is given by A=118c+132h, wh

ere c is the number of city miles driven and h is the number of highway miles driven. If Dema drove 45 mi in the city and used 8 gal of gas, how many highway miles did he drive?
Mathematics
1 answer:
Zigmanuir [339]1 year ago
3 0

We conclude that he drove 176 miles on the highway

<h3>how many highway miles did he drive?</h3>

Here we have the equation:

A = (1/18)*c + (1/32)*h

Where A is the consumption in gallons of gas, c is the number of miles driven in the city and h is the number of miles driven in the highway.

Here we know that:

A = 8 gallons of gas.

c = 45 miles

Replacing that in the above equation, we can find the value of h.

8 =  (1/18)*45 + (1/32)*h

8 - (1/18)*45 = (1/32)*h

32*(8 - (1/18)*45) = h = 176

We conclude that he drove 176 miles on the highway

if you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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Answer:

here i finished!

hope it helps yw!

Step-by-step explanation:

The doubling period of a bacterial population is 15 minutes.

At time t = 90 minutes, the bacterial population was 50000.

Round your answers to at least 1 decimal place.

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We can use the formula:

A = Ao*2^(t/d); where:

A = amt after t time

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Ao * 2^(90/15) = 50000

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Ao = 781.25 is the initial population

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A = 781.25 * 2^(240/15

A = 781.25 * 2^16

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Step-by-step explanation:

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