Question

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Answer 1

If the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1) then the area of the rhombus is 16 square units.

Given the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1).

We are required to find the area of the rhombus when the fourth point Z is plotted.

We have to plot the points of the rhombus in the graph. We know that all the sides of the rhombus should be equal to each other. So by adjusting the blocks in the graph we will be able to plot Z as (-2,3).

In this way the diagonals are ZX and WY.

ZX=$\sqrt{(3-3)^{2} +(6+2)^{2} }$

=$\sqrt{64}$

=8 units

WY=$\sqrt{(1-5)^{2} +(2-2)^{2} }$

=$\sqrt{16}$

=4 units

Area of rhombus=1/2 *($d_{1} *d_{2}$)

=1/2* (8*4)

=8*2

=16 Square units.

Hence if the three vertices of the rhombus are W(2,5),x(6,3),Y(2,1) then the area of the rhombus is 16 square units.

Learn more about rhombus at brainly.com/question/20627264

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