All categories

2 years ago

I need help please please

Mathematics

2 answers:

kotegsom [21]2 years ago

5 0

Answer:

k, a, and i I think!

Step-by-step explanation:

Maslowich2 years ago

5 0

MN, OP, MO, NP, MP. all with the line segment symbol.

You might be interested in

Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours

s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

$cos(x) = \frac{adjacent}{hypotenuse}$

$cos(47) = \frac{22miles}{hypotenuse}$ .... flip both fractions.

$\frac{1}{cos(47)} = \frac{hypotenuse}{22miles}$ .... multiply both sides by 22

$\frac{22mi}{cos(47)} = hypotenuse$

$32.26mi = hypotenuse = B$

So the distance of ship B from the Harbor is 32.26 miles

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0

3 years ago

ABCD Is a rectangle that represents a park.

Andru [333]

Answer:

Shortest distance from A to C = 102.9005 m.

Step-by-step explanation:

It is given that, ABCD is a rectangular park.

The length of the park is 80 m.

The breadth of the park is 50 m.

The diameter of the circle = 15 m.

We have to calculate the shortest distance from A to C across the park.

The distance AC = $\sqrt{50^{2}+80^{2} }$ = 94.339 m.

As one has to pass only through the lines shown, he cannot pass through the circle.

So, we have to subtract the diameter of 15 m from AC

=> 94.339 m - 15 m = 79.339 m.

One must pass through either half of the circumference of the circle.

Since, diameter of circle = 15 m, its radius(r) = $\frac{15}{2}$ = 7.5 m.

The circumference of the circle = 2×π×r = 47.123 m.

Half of the circumference = $\frac{47.123}{2}$ = 23.5615 m.

Distance from A to C passing through circumference = 79.339 m + 23.5615 m = 102.9005 m.

As we have to calculate the shortest distance from A to C, one cannot pass from A to C either through B or D,

since the distance ABC or ADC = 50+80 = 130 m.

Therefore, shortest distance from A to C = 102.9005 m.

3 0

2 years ago

Read 2 more answers

I’m stuck on this one- sorry if I’m annoying lol

Hunter-Best [27]

Answer:

The first statement: "Her first mistake was in Step 2. She added 0.2 to each term instead of multiplying by 0.2."

8 0

2 years ago

A 56 yard loss in football game

o-na [289]

56 yard loss is -56yds

4 0

2 years ago

Cory's average score after 8 tests is 91%. If he gets a 78% on his 9th test what will his new average be?

Luda [366]

You should be able to multiply 91 by 8 to get the sum of the first 8 tests, then add the score on the 9th test. Then to get the average of the sum of the 9 tests you need to divide it by 9.
((91*8)+78)/9=89.555555555555.... So, 90%

3 0

3 years ago