Answer:
Step-by-step explanation:
7+7x
Use a Mohr circle to find the maximum shear stress relative to the axial stress.
Here we assume the axial stress is sigma, the transverse axial stress is zero.
So we have a Mohr circle with (0,0) and (0,sigma) as a diameter.
The centre of the circle is therefore (0,sigma/2), and the radius is sigma/2.
From the circle, we determine that the maximum stress is the maximum y-axis values, namely +/- sigma/2, at locations (sigma/2, sigma/2), and (sigma/2, -sigma/2).
Given that the maximum shear stress is 60 MPa, we have
sigma/2=60 MPa, or sigma=120 MPa.
(note: 1 MPa = 1N/mm^2)
Therefore
100 kN/(pi*d^2/4)=100,000 N/(pi*d^2/4)=120 MPa where d is in mm.
Solve for d
d=sqrt(100,000*4/(120*pi))
=32.5735 mm
Answer:
1.752
Step-by-step explanation:
Nine tenths = 0.9
0.852 + 0.9 = 1.752
Answer:
30
Step-by-step explanation:
6 = 6, 12, 18, 24, <u>30</u>, 36
5 = 5, 10, 15, 20, 25, <u>30</u>, 35
