Answer:
0.818335 ≤ p ≤ 0.86366
Step-by-step explanation:
Given that:
Sample size (n) = 1000
Positive lung cancer = 841
n(p) = 841, p(p) = 841/1000 = 0.841
n(1 - p) = 1000 - 841 = 159
1 - p = 0.159
95% confidence interval
For a 95% confidence interval : z = 1.96
P ± z√p(1-p) / n
0.841 ± 1.96 * √0.841(0.159) / 1000
0.841 - (1.96 * 0.0115636) = 0.818335344
0.841 + (1.96 * 0.0115636) = 0.863664656
0.818335 ≤ p ≤ 0.86366
Let x represent the number.
.. x^2 +x = 2
.. x^2 +x +1/4 = 9/4 . . . . add 1/4 to complete the square
.. x +1/2 = ±3/2 . . . . . . . .square root
.. x = -2, 1
Numbers meeting that requirement are -2 and 1.
Aliyah's paycheck was probaly equal to johns so that would be her average paycheck but if you double it ,it would be more than johns! So john would make $650 in his paycheck